the algorithm is unstable and not optimal. Unlikely to be able to somehow use it or learn something on it)
https://dl.dropbox.com/s/2x15zic85gsbfwb/%D0%BE%D0%B1%D0%BE%D0%BB%D0%BE%D1%87%D0%BA%D0%B0%20100.3dm?dl=1
https://dl.dropbox.com/s/a2avwghhdmb5tv1/%D1%83%D0%BD%D0%B8%D0%B2%D0%B5%D1%80%D1%81%D0%B0%D0%BB%D1%8C%D0%BD%D0%B0%D1%8F%20%D0%BE%D0%B1%D0%BE%D0%BB%D0%BE%D1%87%D0%BA%D0%B0%20100.gh?dl=1…
some i7 if ECC memory sounds an oddity to you). If the model is big you'll need a decent Kepler Quadro as well ... say a K4200 (I hate game cards including Titan).
http://www.tsplines.com/
Alternatively use a top dog subdivision app (Modo eats them all for breakfast) but that works with DX and that brings us back to game cards.…
xtract A1, A2, B1, B2 as one set, A2, A3, B2, B3 as the second set, A3, A4, B3, B4...etc. as the third set and so on. How can I get about doing this?
Any help would be much appreciated!
Thanks,
Ben…
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nologically label them (there are currently 65 points and this is labelled as in the file i've attached). However, what i'm actually after is to reformat these points into an x and y style grid.(a1, a2, a3, a4, a5)(b1, b2, b3, b4, b5)(c1, c2, c3, c4, c5)(d1, d2, d3, d4, d5) etc.Any ideas/help how this can be made possible would be great.Thanks in advance…
gone with the wind topic: since this is utterly Academic the main issue here is to oversimplify LBS (in real life: a collection of columns/beams/slabs/X members + tube frame rigid members (shafts/elevators/cats/dogs)). Reason is that if we use the real "solids" (turned into meshes) as the "node" pool for the hinges required ... only HAL 9000 could solve it in "real-time" (for instance an E5 Xeon 1630 v3 takes ... several minutes). And this is ... er ... challenging I must say. This is a typical case where "simplifying" means "stupidity" almost instantly.
Spam on:
where's my collection of "bend-a-truss-that-looks-like-a-tower" K1 demo defs? Is in this workstation or in another? (blame Alzheimer).
Spam off.
More soon.…
nt B2[i] so B1[i]<=0 means no new connections allowed for point i ,so point i is deleted from B1, B2 updated accordingly.
Initialization:
B1: max number of connections x number of points
B2: all the points
B3: nothing (well null or something, need to create the branch)
Algo:
Get first point in B2, get his allowed number of connections N in B1, find N closest points in B2, create lines in B3, update B2 accordingly. Erase points with max connections (including the first point)
Next
Stop when no points available
At end of loop, B3 stores the created lines.
…