thankssssss
.74-.80 may is ok not big differents .. but i have to control each group of triangles :)
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sorry the version is
rhino 4.9
gr 0.8.0004 version
thanks :)
Added by architecture at 6:26am on December 20, 2011
blinds be (B1,B2..B5). Then the geometry for the five iterations will be ((A+B1), (A+B2)...(A+B5)).
And assume that you are measuring illuminance at four points inside the room (x1,x2,x3,x4) and one point outside the room(y1).
The way Daysim works ( and should work as per the best of my understanding) is that for each setting of the blind (ie. B1,B2,..B5), a separate value of (x1,x2,x3,x4) gets calculated through the Daylight Coefficient Method. So let's say you have illuminance thresholds of (p,q,r,s,t) corresponding to (B1,B2,..B5). What the shade-control algorithm does is that it compares the illuminance at y1 with your threshold of (p,q,..t) and then chooses a value of (x1,x,2,x3,x4) on basis of that. So, when we repeat this process for (365x24=)8760 hours , we end up with a value of a shade setting for each hour which was set on basis of your threshold illuminance values.
I would have gladly answered your question on HB itself, however, I usually work with Daysim directly through commandline.
(BTW, if you are interested in reading more about Daysim google Christoph Reinhart's dissertation on the subject, along with some papers by Zack Rogers).…
ven if the number of panels inside each cell varies. The current solution works when the number of panels inside each cell is always two or other same numbers, but it wouldn't work if the number of panels inside frames are different in each cell. It would be perfect, if numbering of panels are automatically added correctly next to the cell number based on the number of panel division instead of feeding the fixed number.
To take an example, let's assume that the cell #80 has three panels and the #81 has two ones. In this case, three panels within the cell #80 would be numbered like 80-1, 80-2, 80-3, while two panels within the #81 would be numbered such as 81-1 and 81-2 automatically. …
ded a circle and been able to draw the two lines and cull out the correct distances but do not know how to pull out those two original lines - the one from the starting point to the circle division + the circle division to the end point.
To recap - I'm looking for a way to have 2 lines = 80" when the direct path between two points is 60". I do not want the 2 new lines to be equal in length but variable lengths.
thanks!
_patrick
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