. The rules to dispatch the lines are the next:
I start with a list that alternate true/false; like that: true, false, true, false.
If the angles between those lines are greater than 89° I want to inverse the next part of the list:
True, False, True, False, True, False,...
become
True, False, [>89°] False, True, False, True, [>89°] True, False,...
I managed to create a true false list, to check for the greater than 89° angle, to separate the lines relatively to the angles, but I don't know how to inverse part of the list at certain index.
(In the picture, I have written 90° but it should be 89°, I check for greater than 89° and not equal to 90° because in the real rhino model, the lines won't be exactly orthogonal)
If you have another idea to to reach the same result, it's also okay, I tried to find rules to solve the problems, but I may have overlooked other solutions !
And if there is some part of the patch that are correct but there is easier solution, I would love to learn as I am still new to grasshopper.
Thanks for taking the time to read. :)
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CA, DA, DC)Two of those diagonal lengths are obviously redundant but they allow you to simply shift the array to get at different rotational permutations. This makes the search for the nearest mean a bit more straightforward since, in the context of panel clustering, you'd need to consider all rotational permutations of each one.…
Added by David Reeves at 5:26am on November 9, 2014
ole refresh part so that it will try one combination at a time. I dont have a full understanding of how to do this given that everything in GH is runtime.
Outputs: A,B,C,D
A0: Cat
B0: Cat
C0: Cat
D0: Cat
A1: Cat
A2: Cat
A3: Cat
A4: Dog
etc, per refresh.....…
,2,n)
c (0,1,2,n)
And i Would like to have:
d (0(a0+b0+c0),1(a1+b1+c1),n(an+bn+cn) , d being a list of polylines ( triangles in this particular case because an, bn and cn are three sides of a same triangle.)
Thank you…
The overall form is made from 96 unique profiles and is reminescent of a pandanus nut, which is obiquitous in Byron Bay, where it will find its permanent home.