d files have surface divided into rectangular grid, I want that grid hexagonal SO THAT I CAN ATTACH MY HEXAGONAL GEOMETRY IN IT.Hexagon Pattern.3dm,,,,Hexagonal Pattern.ghx…
I have a database with about 80 tables on it, so i wanna connect to the database, make 5/6 different queries, extract the info and use it as an input to grasshopper.
ng long in the x axis and three in the y and they don't all intersect each other... I wrote a script to Boolean difference them but its not working like i want it to . I included a rhino result that id like to achieve in the file. THX -ethan
heres the script:
import rhinoscriptsyntax as rs
b1 = []for i in range(b1L): b1.append (x)print b1bb= len(b1)print bbb2 = []for j in range(b2L): b2.append (y)print b2bc = len(b2)print bc
def bool ():....for i in range (bb):........for j in range(bc):............a = rs.BooleanDifference( b1,b2, False).....return (a) a = bool ()…
ptimization of any kind. If I were to add a space voxelization algorithm to it I could probably do away with 90% of the force vectors in a large particle cloud.
http://www.youtube.com/watch?v=RmsbzTf79bc
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David Rutten
david@mcneel.com
Poprad, Slovakia…
Added by David Rutten at 5:35am on December 16, 2009
e. I want to be able to give it the panels a range let say between 1-3 and then give it a specific number of variations allowed, like only 80 different heights can be generated and the rest of the panels would be rounded up or down to match with one of the 80 heights. would that be possible?
Thanks…
me in 19 different pipeline components. Marginally better, but I'll still need to do this operation approx. 80 times...gulp.
Here's a wishlist request for David: expose string inputs in the Geometry Pipeline for Layer and Name. If I had that, I could change one string to swap my whole geometry set! (My layers have names like "B1 red rail", "B1 blue rail" etc., then the next time I'll want "B2 red rail", "B2 blue rail" etc.)
BTW, I'm happy to script something in C# if it will help: maybe I could write something like the Geometry Pipeline that takes a string input for layer name? Hmmm...
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7,8. It would plot on the line of the 20%, 20%, 70%, 80% of the length of the line. I'm not looking for a way to divide the curve by 2 and then by 2,not steps. So I would have two points at 20%. I hope this is clear.
Thanks,
Tom…