а рабочее зеркало и на любые возникшие вопросы ,всегда ответит круглосуточная поддержка.Самые крутые матчи и ставки с высокими коэффициентами.Не теряйте время!…
. The rules to dispatch the lines are the next:
I start with a list that alternate true/false; like that: true, false, true, false.
If the angles between those lines are greater than 89° I want to inverse the next part of the list:
True, False, True, False, True, False,...
become
True, False, [>89°] False, True, False, True, [>89°] True, False,...
I managed to create a true false list, to check for the greater than 89° angle, to separate the lines relatively to the angles, but I don't know how to inverse part of the list at certain index.
(In the picture, I have written 90° but it should be 89°, I check for greater than 89° and not equal to 90° because in the real rhino model, the lines won't be exactly orthogonal)
If you have another idea to to reach the same result, it's also okay, I tried to find rules to solve the problems, but I may have overlooked other solutions !
And if there is some part of the patch that are correct but there is easier solution, I would love to learn as I am still new to grasshopper.
Thanks for taking the time to read. :)
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ng long in the x axis and three in the y and they don't all intersect each other... I wrote a script to Boolean difference them but its not working like i want it to . I included a rhino result that id like to achieve in the file. THX -ethan
heres the script:
import rhinoscriptsyntax as rs
b1 = []for i in range(b1L): b1.append (x)print b1bb= len(b1)print bbb2 = []for j in range(b2L): b2.append (y)print b2bc = len(b2)print bc
def bool ():....for i in range (bb):........for j in range(bc):............a = rs.BooleanDifference( b1,b2, False).....return (a) a = bool ()…
xtract A1, A2, B1, B2 as one set, A2, A3, B2, B3 as the second set, A3, A4, B3, B4...etc. as the third set and so on. How can I get about doing this?
Any help would be much appreciated!
Thanks,
Ben…
omponent that increases in the x-axis (example below).
A1 A2 A3 A4 A5 etc...B1 B2 B3 B4 B5 etc...C1 C2 C3 C4 C5 etc...D1 D2 D3 D4 D5 etc...
This is as far as I've gotten:
I have collected my points on the grid into a "List Length" component and input that into a "Series" which input into a "Function" with the expression Format("A{0}",x). The result labeling resembles the example below.
A1 A2 A3 A4 A5
A6 A7 A8 A9 A10
A11 A12 A13 A14 A15 etc...
Any help is appreciated.
Thank you in advance.…
gone with the wind topic: since this is utterly Academic the main issue here is to oversimplify LBS (in real life: a collection of columns/beams/slabs/X members + tube frame rigid members (shafts/elevators/cats/dogs)). Reason is that if we use the real "solids" (turned into meshes) as the "node" pool for the hinges required ... only HAL 9000 could solve it in "real-time" (for instance an E5 Xeon 1630 v3 takes ... several minutes). And this is ... er ... challenging I must say. This is a typical case where "simplifying" means "stupidity" almost instantly.
Spam on:
where's my collection of "bend-a-truss-that-looks-like-a-tower" K1 demo defs? Is in this workstation or in another? (blame Alzheimer).
Spam off.
More soon.…
Hi
I'm trying to write a simple script to offset a curve muliptle times (using a 'for loop') but I don't know the vb dotNet syntax. I'm sure lines 84, 88 & 89 are wrong. Any ideas.
Thanks. P
Added by Paul Wintour at 8:25am on September 28, 2010
dro). The quality of the driver is also critical: hard to imagine NVidia working overnight to fix "some" driver bugs due to requests from gamers. Game cards are notoriously bad in dual monitor configurations.
3. A zillion of cores (triumph of marketing VS common sense) divided by the given clock rate ... gives you just ONE poor old core (Rhino/gh are single-threaded apps) that tries to do the job.
4. Single Xeon E5 2xxx V3 (the higher the clock the LESS the cores = better) would be my recommendation. ECC fast memory is also a must.
PS: Find a friend who operates a "loaded" H/P Z840 and test your defs.
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