old version that has been fixed by now. I'd ask you to test this on the Rhino6 beta (which I am using to test this), but it looks like you're using a cracked version of Rhino so you probably don't have access to that.…
nologically label them (there are currently 65 points and this is labelled as in the file i've attached). However, what i'm actually after is to reformat these points into an x and y style grid.(a1, a2, a3, a4, a5)(b1, b2, b3, b4, b5)(c1, c2, c3, c4, c5)(d1, d2, d3, d4, d5) etc.Any ideas/help how this can be made possible would be great.Thanks in advance…
) function if you've already got a boolean value.
This expression:
x < 12
results in exactly the same things as this expression:
If( x < 12, True, False )
If() is only really useful when you want to return non-boolean data, like so:
If( x < 12, x, 100-x )
In this case, the expression will return either x, or 100-x if x is larger than or equal to 12:
x result
1 1
2 2
10 10
11 11
12 88
13 87
14 86
18 82
70 30
--
David Rutten
david@mcneel.com
Poprad, Slovakia…
Added by David Rutten at 7:22am on August 10, 2011
Hello Sir
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ine 114, in AddCurve, "C:\Documents and Settings\Panos\Application Data\McNeel\Rhinoceros\5.0\Plug-ins\IronPython (814d908a-e25c-493d-97e9-ee3861957f49)\settings\lib\rhinoscript\curve.py" line 91, in script
line 91: newcurve = rs.AddCurve(arrNewPos,Rebuild)
Is there any possible idea for what is going wrong?
Any help would be greatly appreciated.
…
, a1200)}) Is there any way I can make this list into {a1, a2, a3, a4, -a5, -a6, -a7, -a8, a9, a10, a11, a12, -a13, ..... , a1200} ? ( 4 positive signs then 4 negative signs and so on) - alternating every nth in general.
or
2. Is there any way (workaround) to get negative angle value from 2 vectors? I know 'ANGLE (of 2 vectors)' component by itself doesn't work and I know why too. I have feeling that the reflex angle output might be useful but again, matter of list manipulation.
Any help would be greatly appreciated. Thanks in advance.
Hyo
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