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Added by kavehoshkooh at 3:25pm on September 11, 2015
blinds be (B1,B2..B5). Then the geometry for the five iterations will be ((A+B1), (A+B2)...(A+B5)).
And assume that you are measuring illuminance at four points inside the room (x1,x2,x3,x4) and one point outside the room(y1).
The way Daysim works ( and should work as per the best of my understanding) is that for each setting of the blind (ie. B1,B2,..B5), a separate value of (x1,x2,x3,x4) gets calculated through the Daylight Coefficient Method. So let's say you have illuminance thresholds of (p,q,r,s,t) corresponding to (B1,B2,..B5). What the shade-control algorithm does is that it compares the illuminance at y1 with your threshold of (p,q,..t) and then chooses a value of (x1,x,2,x3,x4) on basis of that. So, when we repeat this process for (365x24=)8760 hours , we end up with a value of a shade setting for each hour which was set on basis of your threshold illuminance values.
I would have gladly answered your question on HB itself, however, I usually work with Daysim directly through commandline.
(BTW, if you are interested in reading more about Daysim google Christoph Reinhart's dissertation on the subject, along with some papers by Zack Rogers).…
, a1200)}) Is there any way I can make this list into {a1, a2, a3, a4, -a5, -a6, -a7, -a8, a9, a10, a11, a12, -a13, ..... , a1200} ? ( 4 positive signs then 4 negative signs and so on) - alternating every nth in general.
or
2. Is there any way (workaround) to get negative angle value from 2 vectors? I know 'ANGLE (of 2 vectors)' component by itself doesn't work and I know why too. I have feeling that the reflex angle output might be useful but again, matter of list manipulation.
Any help would be greatly appreciated. Thanks in advance.
Hyo
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Added by MichaelD0112 at 12:25am on April 10, 2023
nt B2[i] so B1[i]<=0 means no new connections allowed for point i ,so point i is deleted from B1, B2 updated accordingly.
Initialization:
B1: max number of connections x number of points
B2: all the points
B3: nothing (well null or something, need to create the branch)
Algo:
Get first point in B2, get his allowed number of connections N in B1, find N closest points in B2, create lines in B3, update B2 accordingly. Erase points with max connections (including the first point)
Next
Stop when no points available
At end of loop, B3 stores the created lines.
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