urs x 365 days ), and with modulus in the screenshot above, i could manage to do for every hour. but sometimes in my definition, i have a range from 1 to 35040, which is 365 x 24 x 4 ( 4 here defines every 15 minutes), on other word, when the number is one, then i have 01:00 O'Clock, when the number is 2 then i have 01:15 O'clock, when the number is 3 then i have 01:30 O'Clock...etc , so when the number is 97, which is the next day ( and after the number 96 which is equal 24 hours x 4), then I should have again 01:00 O'Clock.
I hope my idea is clear, thanks in advance!
Nassif…
behave like this:{a1;b2;c3;d1;e2;f3;g1;h2}
The ping pong matching would behave like this:
{a1;b2;c3;d2;e1;f2;g3;h2}
with a boolean option it could repeat the first and last like this:
{a1;b2;c3;d3;e2;f1;g1;h2}
If this already exist please let me know
Thanks
bye…
Added by Frane Zilic at 10:15pm on August 19, 2012
Hi Joseph,
have you tried unifying the sequence of pictures with something like http://www.virtualdub.org/, and then loading the sequence in AE?
- Giulio
______________giulio@mcneel.comMcNeel Europe
ng long in the x axis and three in the y and they don't all intersect each other... I wrote a script to Boolean difference them but its not working like i want it to . I included a rhino result that id like to achieve in the file. THX -ethan
heres the script:
import rhinoscriptsyntax as rs
b1 = []for i in range(b1L): b1.append (x)print b1bb= len(b1)print bbb2 = []for j in range(b2L): b2.append (y)print b2bc = len(b2)print bc
def bool ():....for i in range (bb):........for j in range(bc):............a = rs.BooleanDifference( b1,b2, False).....return (a) a = bool ()…
ider and a list item component to select a particular brep A or B or C, without selecting a particular breq inside each of them?
It seems the merge function will merge all the breqs inside each of the breps into one flattened list ...…