CA, DA, DC)Two of those diagonal lengths are obviously redundant but they allow you to simply shift the array to get at different rotational permutations. This makes the search for the nearest mean a bit more straightforward since, in the context of panel clustering, you'd need to consider all rotational permutations of each one.…
Added by David Reeves at 5:26am on November 9, 2014
سلام آقای جان بیلی کاوه اشکوه هستم اپراتور سی ان سی از ایران وطراح دکوراسیون داخلی اگر ممکن هستش فایل اصلی میزcosinosa baram mail konid adressmail man hast
(kavehoshkooh2290@gmail.com)بسیار متشکرم
Added by kavehoshkooh at 3:25pm on September 11, 2015
ng long in the x axis and three in the y and they don't all intersect each other... I wrote a script to Boolean difference them but its not working like i want it to . I included a rhino result that id like to achieve in the file. THX -ethan
heres the script:
import rhinoscriptsyntax as rs
b1 = []for i in range(b1L): b1.append (x)print b1bb= len(b1)print bbb2 = []for j in range(b2L): b2.append (y)print b2bc = len(b2)print bc
def bool ():....for i in range (bb):........for j in range(bc):............a = rs.BooleanDifference( b1,b2, False).....return (a) a = bool ()…