blinds be (B1,B2..B5). Then the geometry for the five iterations will be ((A+B1), (A+B2)...(A+B5)).
And assume that you are measuring illuminance at four points inside the room (x1,x2,x3,x4) and one point outside the room(y1).
The way Daysim works ( and should work as per the best of my understanding) is that for each setting of the blind (ie. B1,B2,..B5), a separate value of (x1,x2,x3,x4) gets calculated through the Daylight Coefficient Method. So let's say you have illuminance thresholds of (p,q,r,s,t) corresponding to (B1,B2,..B5). What the shade-control algorithm does is that it compares the illuminance at y1 with your threshold of (p,q,..t) and then chooses a value of (x1,x,2,x3,x4) on basis of that. So, when we repeat this process for (365x24=)8760 hours , we end up with a value of a shade setting for each hour which was set on basis of your threshold illuminance values.
I would have gladly answered your question on HB itself, however, I usually work with Daysim directly through commandline.
(BTW, if you are interested in reading more about Daysim google Christoph Reinhart's dissertation on the subject, along with some papers by Zack Rogers).…
ng long in the x axis and three in the y and they don't all intersect each other... I wrote a script to Boolean difference them but its not working like i want it to . I included a rhino result that id like to achieve in the file. THX -ethan
heres the script:
import rhinoscriptsyntax as rs
b1 = []for i in range(b1L): b1.append (x)print b1bb= len(b1)print bbb2 = []for j in range(b2L): b2.append (y)print b2bc = len(b2)print bc
def bool ():....for i in range (bb):........for j in range(bc):............a = rs.BooleanDifference( b1,b2, False).....return (a) a = bool ()…
pe and its surface.
However, I don't have that much knowledge about both grasshopper and Mathematica.. I mean I can only make assumptions and think about relations of certain functions but that's all.
If you can help me on this, I would appreciate it so much.
You can see a screenshot of the code and model of the demonstration from mathematica in attachment.
And here is the mathematica code;
Manipulate[ Module[{\[CurlyEpsilon] = 10^-6, c1 = Tan[a1], c2 = Tan[a2], c3 = Tan[a3], c4 = Tan[a4], c5 = Tan[a5], c6 = Tan[a6]}, ContourPlot3D[ Evaluate[ c6 Sin[3 x] Sin[2 y] Sin[z] + c4 Sin[2 x] Sin[3 y] Sin[z] + c5 Sin[3 x] Sin[y] Sin[2 z] + c2 Sin[x] Sin[3 y] Sin[2 z] + c3 Sin[2 x] Sin[y] Sin[3 z] + c1 Sin[x] Sin[2 y] Sin[3 z] == 0], {x, \[CurlyEpsilon], Pi - \[CurlyEpsilon]}, {y, \[CurlyEpsilon], Pi - \[CurlyEpsilon]}, {z, \[CurlyEpsilon], Pi - \[CurlyEpsilon]}, Mesh -> False, ImageSize -> {400, 400}, Boxed -> False, Axes -> False, NormalsFunction -> "Average", PlotPoints -> ControlActive[10, 30], PerformanceGoal -> "Speed"]], {{a1, 1, "\!\(\*SubscriptBox[\(\[Alpha]\), \(1\)]\)"}, -Pi/2 - 0.01, Pi/2 + 0.01, ImageSize -> Tiny}, {{a2, 1, "\!\(\*SubscriptBox[\(\[Alpha]\), \(2\)]\)"}, -Pi/2 - 0.01, Pi/2 + 0.01, ImageSize -> Tiny}, {{a3, 1, "\!\(\*SubscriptBox[\(\[Alpha]\), \(3\)]\)"}, -Pi/2 - 0.01, Pi/2 + 0.01, ImageSize -> Tiny}, {{a4, 1, "\!\(\*SubscriptBox[\(\[Alpha]\), \(4\)]\)"}, -Pi/2 - 0.01, Pi/2 + 0.01, ImageSize -> Tiny}, {{a5, 1, "\!\(\*SubscriptBox[\(\[Alpha]\), \(5\)]\)"}, -Pi/2 - 0.01, Pi/2 + 0.01, ImageSize -> Tiny}, {{a6, 1, "\!\(\*SubscriptBox[\(\[Alpha]\), \(6\)]\)"}, -Pi/2 - 0.01, Pi/2 + 0.01, ImageSize -> Tiny}, AutorunSequencing -> {1, 3, 5}, ControlPlacement -> Left]…
t it is rounded to 25, 100, 75. I've figured out the rounding portion, but when I plug the resulting list back into the custom preview, it doesn't recognize the data. I'm guessing it is because my rounded list is in curly brackets, whereas the unrounded data straight from the image sampler is not. How can I process this to remove the curly brackets?
Thanks,
Ryan
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Added by Ryan Dirks at 5:20pm on September 18, 2014