behave like this:{a1;b2;c3;d1;e2;f3;g1;h2}
The ping pong matching would behave like this:
{a1;b2;c3;d2;e1;f2;g3;h2}
with a boolean option it could repeat the first and last like this:
{a1;b2;c3;d3;e2;f1;g1;h2}
If this already exist please let me know
Thanks
bye…
Added by Frane Zilic at 10:15pm on August 19, 2012
he code within a limited number of turns. I suggest you check 양방하는법 and learn more interesting things about games. The game is not only challenging and fun, but it also helps to improve cognitive skills such as critical thinking, problem-solving, and pattern recognition. Mastermind has stood the test of time and remains a beloved game for all ages.…
Added by MichaelD0112 at 12:25am on April 10, 2023
ng long in the x axis and three in the y and they don't all intersect each other... I wrote a script to Boolean difference them but its not working like i want it to . I included a rhino result that id like to achieve in the file. THX -ethan
heres the script:
import rhinoscriptsyntax as rs
b1 = []for i in range(b1L): b1.append (x)print b1bb= len(b1)print bbb2 = []for j in range(b2L): b2.append (y)print b2bc = len(b2)print bc
def bool ():....for i in range (bb):........for j in range(bc):............a = rs.BooleanDifference( b1,b2, False).....return (a) a = bool ()…
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Added by kavehoshkooh at 3:25pm on September 11, 2015
nt B2[i] so B1[i]<=0 means no new connections allowed for point i ,so point i is deleted from B1, B2 updated accordingly.
Initialization:
B1: max number of connections x number of points
B2: all the points
B3: nothing (well null or something, need to create the branch)
Algo:
Get first point in B2, get his allowed number of connections N in B1, find N closest points in B2, create lines in B3, update B2 accordingly. Erase points with max connections (including the first point)
Next
Stop when no points available
At end of loop, B3 stores the created lines.
…