the first area and the first number, the second area and the second number and the third are and the third number. For example, let's assume we have the following areas {65, 15, 20}. The absolute difference between these two sets equals {abs(44-65), abs(39-15), abs(17-20)} == {21, 24, 3}. The sum-total of all these absolute differences is your fitness, i.e. 21+24+3 = 48. This number has to go to zero.
If we enter the results you just got, then the absolute differences look like this: {abs(44-44), abs(39-17), abs(17-39)} == {0, 22, 22}, which results in a fitness of 44. Only an exact match will result in a fitness of zero.
--
David Rutten
david@mcneel.com
Seattle, WA…
Added by David Rutten at 12:44pm on November 13, 2010
13;2} ... 20.{13;12}
21. {21;0}22. {21;1}23. {21;2} ... 41. {21;20}
42. {34;0}43. {34;1}44. {34;2} ... 75. {34;33}
76. {55;0}77. {55;1} ... ....
I want to grab the first 8 [0-7], the next 13[8-20], the next 21[21-42] etc
so i have the (known fibonacci seq) list of numbers on the left here:
C S
8 0
13 8
21 21
34 42
55 76
89 131
144 220
233 364
and i need the list on the right, so that i can select items using a Series (N=1 and S and C from the list above) and a List Item component.
the simple question is:
is there a component that can take a list and accumulate it in this way that I need?
if not, is there anyone that can point me to a simple relevant VB example so i could easily adapt it?
many thanks,
gotjosh…
element connectivities in text, when matched with the corresponding coordinates of the nodes from dupPt, it makes all the polygons again (Green lines in the picture below), exactly as the original.
So Im thinking its like reconstructing everything again from the original shape with new relation between coordinates and element connectivities.
So in this case, eg: 0 1 2 3 4 5 makes the hexagon, 21 20 0 5 to makes the trapz.
Well here it misses the '0' in the end to close the hexagon here, the same with trapz. However the 'string join' and cset somehow close it to 0 1 2 3 4 5 0 to makes the hexagon, and 21 20 0 5 21 for trapz.
Im very glad now.
…
t case point 3 should be able to move from 20 to 33
so in other word
pt 3 depends on pt 2
the problem is if i only have sliders
pt2 could be 20
and pt 3 could be 20, that is higher than 33
so the loft loops in itself
gracias por tu ayuda
salu2
m…
SiTI - Politecnico di Torino + ETH Computational Assessment Workshop at ETH - ValueLab - March 20, 2012 Assessment of 3 scenarios on the development of the F...