(18, 11, 0, 17), also put in the assembly component.
How can I know which value of the reaction forces correspond to which support?
In the manual is stated that when the reaction force component is used, than the values are displayed in ascending sequence of the corresponding nodes.So if I input the support nodes like thispoint with index 18point with index 11point with index 0point with index 17are the reaction forces displayed like this (per loadcase)?0 - reaction forces in point with index 01 - reaction forces in point with index 112 - reaction forces in point with index 183 - reaction forces in point with index 17
Thanks!
BestLara…
he default for Rhino, degree=5 gives you smoother curves, but each control point matters less, degree=11 is the highest degree Rhino allows. Apart from 2, degrees tend to be odd rather than even, though Rhino supports both.
In addition to the degree and the control points, Nurbs curves have knots. A single knot is just a number, and the list of all knots is called the knot-vector of a curve. The number of knots depends on both the degree and the control-point count, and the spacing of the knots affects the shape of the curve a little bit. If there are <degree> knots with the same value, then the curve is somewhat discontinuous at that location which could manifest itself as a kink or as a clamped end-point. However it is not possible by just looking at the shape of a curve to say where stacked knots might be, but you can use the Rhino _List command to inspect all details of a Nurbs curve.…
ital; aproveche esta oportunidad y vea la demostración en vivo: Lugar: Escuela Digital - Mexico D.F. Hora: 7:00 - 9:00 pm Con el apoyo de: ESCUELA DIGITAL - Metzli Valle metzli@escueladigital.com.mx…
I've attached a rh and ghx file. http://we.tl/ghsd0UTxji - wetransfer link. I'm guessing the trick is to correctly define the Range (R) / Domain in the Random component, so that the circles' radi can vary between the fixed and static domain of 10 or 12 or 14 or 18 or 20. Meaning that the radi can only be 10, 12, 14, 18 or 20 - and not, lets say.. 11, 13, 15, 16, 17 or 19 for that matter. Thanks in advance, i hope someone can figure it out, because i can't seem to find anything online about how to set up such as specific domain.
…
ay be other issues with your geometry, but this is usually the issue people run into.)
Rays will lose energy much more slowly when a room is very reflective, but such conditions only really exist with polished painted concrete. I don't know how many such rooms you've ever been in. I can count them on one hand - and I've been to acoustic reverberation chambers on 3 continents.
Pachyderm works with a ray decimation algorithm. This means that a ray will be traced out to the cutoff time, unless it has lost enough energy that its further contribution to the impulse response is negligible. At this time, the ray is discontinued. So, the more absorption in the room, the less time it will take to run the simulation. So, more realistic absorption coefficients will allow a model to run in a more reasonable amount of time.
Gypsum board/Plasterboard will typically be between 8 and 11 percent at mid and high frequencies, and higher at low frequencies, for example. Concrete, unless polished and painted, is still a little porous, so you can probably make it 3 to 5 percent.
Regarding sources and receivers, adding more receivers adds almost nothing to calculation time (until the every end, when it extrapolates a pressure response, anyway). This is because the receivers are entered into a spatial partition system, which allows it to be done in an optimized way. Adding multiple sources will effectively multiply the calculation time by the number of sources, because the simulation needs to be repeated for each source individually.
Hopefully this helps you figure out how to run simulations with reasonable run times.
Arthur…
ore limited way to achieve similar results.Specifically I am looking for a way to apply a transformation (not necessarily geometric, but a general one) to a data stream a pre-defined number of times, and collect all the partial results. For example, take a point, apply the transformation "rotate by 30 degrees around the origin" 11 times to get 12 points on a circle (of course this specific problem can be solved in other ways, it is just an illustration of what I mean). This would allow creating fractal-like structures.An unrelated question: is there a built-in constant for π (pi), or is it necessary to type the value explicitly every time when setting it as a number somewhere?…
ated in all editions of Architektura Parametryczna Workshops!Architektura Parametryczna Workshops Optimization Warsaw 2016 FAQWHEN?21-22nd May 2016 (Saturday-Sunday)HOW LONG DO THE WORKHSOPS LAST?The workshops last in total 16 hours.Saturday 10AM -7PM (with lunch break), Sunday 10AM -7PM (with lunch break)WHAT WILL I LEARN?On Saturday the optimization processes with solar, views and structural analysis will be explored. We will be discovering optimal solutions with the help of plug-ins such as Galapagos, Silvereye, Octopus, Karamba and Ladybug. In the Sunday morning we will learn how to present the results of the optimization: creating catalogues of solutions and printing the optimization graphs. In the afternoon participants will have time for the development of the personal project. HOW MUCH DOES IT COST?The workshops cost 600 PLN (or 160€) for Early Bird payments and 700 PLN (or 190€) for the regular payments. The 3-person group - 1500 PLN (or 440€ )EARLY BIRD?For those who are certain that they will attend the workshops, we have a special Early Bird offer till 30th of April 2016.HOW CAN I SIGN UP?Send an email to info@architekturaparametryczna.pl with the title: “OPTI WAW 16”.HOW MANY PLACES ARE AVAILABLE?We have only 11 places!WORKSHOPS: Level: intermediate – advancePerquisites: the basic knowledge of Rhino and Grasshopper3D. Plug-ins: Silvereye, Octopus, Ladybug, Karamba. Weaverbird. Python GHThe main aim of the 16-hour workshops is to give the participants the understanding of how the optimization process can be used in practice and how it can help in solving everyday design problems. The practical exercise will be supported with the short lectures explaining the theoretical background of the optimization algorithms. The general program of the Optimization Warsaw 2016 Workshops*:1. Optimization of the facade geometry with solar analysis.2. Optimization of the roof structures with Karamba.3. Finding the optimal configuration of the space frame structures with Karamba.4. Discovering the best location or/and geometry of the building in accordance to the best views from the plot.5. Presentation of the discovered solutions. *Some of the exercises might be changed.…
) function if you've already got a boolean value.
This expression:
x < 12
results in exactly the same things as this expression:
If( x < 12, True, False )
If() is only really useful when you want to return non-boolean data, like so:
If( x < 12, x, 100-x )
In this case, the expression will return either x, or 100-x if x is larger than or equal to 12:
x result
1 1
2 2
10 10
11 11
12 88
13 87
14 86
18 82
70 30
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David Rutten
david@mcneel.com
Poprad, Slovakia…
Added by David Rutten at 7:22am on August 10, 2011
lane that looks like the outline of a gear wheel
2. Scale a bunch of copies of the curve to different sizes (I use 11 different sized curves.)
3. Move each curve vertically to a different Z-height
4. Rotate each curve to get the desired wavy/wiggly effect
5. Create a Loft surface using all the curves.
A critical step when creating the Loft is to add the curves in order - either top to bottom or bottom to top.
Step 4 can be omitted if you want a constant curvature throughout the final part. In this case all you have to do is Twist by the desired amount the Loft surface made from un-rotated curves. …
Added by Birk Binnard at 2:18pm on October 15, 2016
ings" [every person on the experiment is one ring] which show the time duration. The outer sphere is divided in 11 segments [which are basically the segments of a human brain] I hav imported the data so far but what i aim is to find a way to connect each moment[time, second] from the inner sphere to a number of points from a specific segment in the outer. For example for Person number1, at 5th second the segments that are activated are 4th , 6th, 11th with 2, 3, 2 points.
It could be done manually but since the connections are a few thousands and i got the lists, i wonder whether there is a better way.
Any help is appreciated, i do not attach files since you need the excel files aswell. If anyone would like to help i can email the files.
Thanks in advance.…