the catenary shape
6) Get the mid point of all the heaxgons
7) Create surfaces to get the average normal of each hexagons
8) Project the hexagon on the normal plane
9) Move the plane using the normals
10) create mesh faces between first and second hexagons
11) create mesh faces to close the planar hexagon
12) Orient all the mesh faces on a flat grid to laser cut them
13) Join and weld the mesh
14) Thicken the mesh using Weaverbird to get a shell
I hope this helps. It is all one mesh at the end made of quads on the side and triangles on the top (yes 6 of them).
All the best,
Arthur
…
fault materials...6 RAD materials are loaded1. 2. Downloading OpenStudioMasterTemplate.idf to c:\ladybug\3. Loading EP construction library4. 206 material found in c:\ladybug\OpenStudioMasterTemplate.idf5. 30 windowmaterial found in c:\ladybug\OpenStudioMasterTemplate.idf6. 284 construction found in c:\ladybug\OpenStudioMasterTemplate.idf7. Loading EP schedules...8. The ScheduleTypeLimits: Fraction is already existed in the libaray.You need to rename this ScheduleTypeLimits.9. The ScheduleTypeLimits: Temperature 7 is already existed in the libaray.You need to rename this ScheduleTypeLimits.10. 21 scheduletypelimits found in c:\ladybug\OpenStudioMasterTemplate.idf11. 1370 schedule found in c:\ladybug\OpenStudioMasterTemplate.idf12. 13. 14. Hooohooho...Flying!!Vviiiiiiizzz...…
this, you'll have no horizontal force at the roller, but you will have it at the pinned support. If you wouldn't, then the structure will be displaced.
Usually, in 2 dimensional structures, if you want to know if an articulated structure is isostatic (as opposed to hyperstatic, which is what you have right now) is to use the following formula:
b+c-2·n=0;
b being the number of bars, c the number of constraints you have and n the number of nodes. In your case: b=19, c=3 (displacements constrained in X, Z at your pinned support and only constrained in Z at your roller support) and n=11, so: 19+3-2·11=0.
I recommend you to download the app SW Truss, as it's very useful to check your results instantly.…
300895
FB: https://www.facebook.com/ChidoStudio
FB: https://www.facebook.com/WEDOTdesign
Detalles:
Instructores:
Arturo de La Fuente (Chido Studio Argentina)
Eliana Monaco (Chido Studio Argentina)
Luis de La Parra (Chido Studio Mexico)
WS ROSARIO
Lugar:
DOSCASAS
ROSARIO: Sarmiento 1232 Planta Alta (2000 Rosario)
Fechas:
Viernes 16 de Mayo 2014 – 11:00 – 19:00 hs
Sábado 17 de Mayo 2014 – 11:00 – 19:00 hs
Domingo 18 de Mayo 2014 – 11:00 – 19:00 hs.
WS BUENOS AIRES
Lugar:
GARAGELAB
BsAs: Roseti 1380 CABA
Fechas:
Jueves 22 de Mayo 2014 – 18:00 – 21:00 hs
Viernes 23 de Mayo 2014 – 18:00 – 21:00 hs
Sábado 24 de Mayo 2014 – 11:00 – 20:00 hs.
Domingo 25 de Mayo 2014 – 11:00 – 20:00 hs
Importante:
Todos los niveles de experiencia son bienvenidos el único requisito es tener un entendimiento básico de los programas CAD y una actitud positiva hacia el aprendizaje de dichas herramientas. Necesitas llevar una laptop, nosotros te instalamos los programas de prueba.
Si planeas venir de fuera de la ciudad avísanos y te pondremos en contacto con otras personas que también vayan a hacerlo para en caso de desearlo puedan compartir su lugar de estancia.
Al participar en el workshop obtienes el 50 % de descuento en la licencia educacional Rhinoceros por medio de Rhino Chile.
COSTOS:
Profesionales: $1600
Estudiantes: $1400
Si ya realizaste algún Workshop de Chidostudio tenes un 20% descuento en esta inscripción.
Si venis en grupo con 2 amigos más cada uno tiene un %20 de descuento.
Proceso de Inscripción:
El participante deberá un mail a bsas@chidostudio.com donde se le enviará el procedimiento y medios de pago.
El depósito mínimo para reservar la matrícula es del 50% el resto deberá ser cubierto el día del evento.
Una vez que el depósito se haya llevado a cabo el participante deberá enviar a este correobsas@chidostudio.com los siguientes datos:
Nombre completo
Email
Teléfono
Institución educativa u Oficina
Archivo adjunto del recibo del depósito bancario
En cuanto recibamos la información immediatamente nos pondremos en contacto para especificar los pasos a seguir.
Contacto:
Arturo de La Fuente
bsas@chidostudio.com
Tel: (+54) 11-57268799
…
not sure about my method used to obtain the result.I think is really complex; do you know a smart method to simplify all my equation?
thanks guys!! :D…
rcle A 0---1---2Circle B 0---1---2---3---4---5---6---7---8---9---10---11I was actually trying to connect through separated lines, point (A,0) to (B,11) and (B,1),point (A,1) to point (B,3) and (B,5), and (A,2) to (B,7) and (B,9).I was able to do it using a list item selecting the points and creating a line between them, but i would be to long to do it if i would like to divide in many more points, and try to connect them using list item... i went looking around for a bit, i think its possible to do it with a path mapper or a flip matrix, althought i have no clue how to make it.
You will find enclosed, some screenshots...If anyone could give me any tip, i thank you all in advance.Have a nice day.+Joan…
Added by Joan tarragon at 7:38am on December 5, 2011
idually and by group
3) Clean up functions to discard failed results
4) Use generated images using windows directories to delete designs (so you can bring one next to each other and discard similar ones)
5) Hide irrelevant parameters
6) View generated images in zoom
7) Individually set limits on filter parameters (using sliders)
8) Reload CAD file without having to close and open genoform
9) Much smaller UI (we want to allow the screen for design work, so the functionalities have been made into pop-ups).
10) Navigate in view to a desired design (by number)
11) Any other features our users want ? (let us know)
We hope that this version is much more easier to use and allows designers to manage what they wish to generate section by section or layer by layer.…
ult, my 3dm is very large.
Another problem, when the fonction is ok, the draw in grasshopper is ok, when i bake i have only a litte part of the opération.....
If you could help me, thank you
[Edit] Here the description in the null item :
{0;0}0. Brep: brep.m_T[43047] trim is not valid. trim.m_type = seam, the edge is manifold, but brep.m_L[trim.m_li=1114].m_type is not outer.brep.m_L[1114] loop is not valid. brep.m_T[loop.m_ti[21]=43047] is not valid.brep.m_F[0] face is not valid. brep.m_L[face.m_li[1114]=1114] is not valid.ON_Brep.m_F[0] is invalid.1. 2. 3. 4. 5. 6. 7. 8. 9. 10. 11. 12. …
number of divisions on that curve as in the defintion (i.e. by 4). The offset in the def is slightly different and should cull two or three more curves as in the lists that show my aim below.
Basically I want to look into each branch of the groups of points from each closed curve . Marking in a list whether it contains a one or a zero (0= outside 1 = coincidents).
{0;0}0. 21. 22. 23. 2 {0;1} 0. 01. 22. 03. 2 {0;2}0. 01. 02. 03. 0 {0;3}0. 21. 22. 23. 2 {0;4}0. 21. 22. 23. 2 {0;5}0. 21. 22. 23. 2 {0;6}0. 01. 22. 23. 1 {0;7}0. 21. 22. 03. 0 {0;8}0. 21. 22. 23. 2 {0;9}0. 21. 22. 23. 2 {0;10}0. 21. 22. 23. 2 {0;11}0. 21. 22. 23. 2 {0;12}0. 21. 22. 23. 2 {0;13}0. 01. 22. 23. 0 {0;14}0. 21. 22. 23. 2
I want to create a list from these points. That marks each curve that pokes out, in a cull pattern as such:
20022210222202
Using a 1 where there are co-incidents in the curve points and the boundary. A 2 for true (outside points) and a 0 for containment. So I might be able to use the 1 in future developments - however if a true false list is easiest I can live with that.
So could I use F(x) function? - to look for 0 or 1's in each bunch of points and thus list as such for a cull pattern? or will Path mapper help me here? Or can I rely on simply grafting and splitting??
I am usure of the neatest solution and would love to learn. Hope you can direct me.rgrds
J.…