al number 1 represents 1/1/1900 12:00:00 a.m. Times are stored as decimal numbers between .0 and .99999, where .0 is 00:00:00 and .99999 is 23:59:59. The date integers and time decimal fractions can be combined to create numbers that have a decimal and an integer portion. For example, the number 32331.06 represents the date and time 7/7/1988 1:26:24 a.m.
More info: http://support.microsoft.com/kb/214094…
Added by Ángel Linares at 4:50pm on November 27, 2010
output will show a tree with 3 branches of 4 integers each that I can pass on to other components. What is the best way to do it?
I have tried creating a tree and using a for loop to do so, but it didn't work.
Thank you for your help.
…
hink you need recursion to modify the random seed; many other ways to accomplish that (use the length of each curve as the seed, for example).
Using multiples of twelve makes it harder for me to grasp the essence of the matter; another way of looking at it is that you want to generate random integers from 2 to 5 (24,36, 48 and 60) and have them add up exactly to curve lengths of 5 (x12=60), 9 (x12=108) or 14 (x12=168).
So you want to generate random numbers until their sum ('Mass Addition') plus 5 is equal to or greater than the curve length (5, 9 or 14). The last number in the series is then not random but just the difference between the two.
For example, for curve length = 5 (x12=60), there are only three possible numbers that can be used as the first in the sequence: 2, 3 or 5. If it's 5, you're done. If it's 2, the second number is 3 (5-2), if it's 3, the second number is 2 (5 - 3). You can't use '4' at all because the remainder, 1 (x12=12) isn't one of your solution options.
There is no point in generating the last number randomly, eh?
P.S. You didn't use 'Internalize data' for the 'Curve (Crv)' param in your GH file.…
Added by Joseph Oster at 2:29pm on September 12, 2015
EC
1. Between hours 1:00 to 24:002. Current document units is in Meters3. Conversion to Meters will be applied = 1.0004. [1 of 7] Writing simulation parameters...5. [2 of 6] No context surfaces...6. [3 of 6] Writing geometry...7. [4 of 6] Writing materials and constructions...8. [5 of 7] Writing schedules...9. [6 of 7] Writing loads and ideal air system...10. [7 of 7] Writing outputs...11. ...... idf file is successfully written to : c:\ladybug\Freeformtower_IDF\EnergyPlus\Freeformtower_IDF.idf12. 13. Analysis is running!...14. ......
Done! Read below for errors and warnings:
15. 16. Program Version,EnergyPlus-Windows-64 8.1.0.009, YMD=2015.04.04 23:39,IDD_Version 8.1.0.00917. 18. ************* IDF Context for following error/warning message:19. 20. ************* Note -- lines truncated at 300 characters, if necessary...21. 22. ************* 577 Zone,23. 24. ************* Only last 1 lines before error line shown.....25. 26. ************* 578 Freeformbuilding27. 28. ** Warning ** IP: IDF line~578 Comma being inserted after:" Freeformbuilding" in Object=ZONE29. 30. ** Severe ** Out of range value Numeric Field#5 (Type), value=0.00000, range={>=1 and <=1}, in ZONE=FREEFORMBUILDING31. 32. ************* IDF Context for following error/warning message:33. 34. ************* Note -- lines truncated at 300 characters, if necessary...35. 36. ************* 586 BuildingSurface:Detailed,7341.
…
} (N=11) {0;1} (N=11) {0;2}(N = 11) {0;3}(N = 11) {0;4}(N = 11)
2. I run the Points that are coming out from the Divide Curve Components through the Path Mapper components with this definition:
{A;B} (i) > {A} (i)
3. I run data coming out from Path Mapper component through:
a) Parameter Viewer component and the result is:
{0} N=11 (data with 1 branches)
b) Point > Panel and the result is:
collection of 11 point (N=11) which is the exactly the same as the collection of point belonging to {0;4} (N = 11).
So, here is the question:
why the collection of points coming out from the Path Mapper {A;B} (i) > {A} (i) component is the same as the collection of points belonging to the curve {0;4}(N = 11) ?
Anyway ... It 's the first time I ask a question here... so I would like to thank you for what you do with your work! Thank you! You are really great!…
Each corner of mesh A has got a partner on mesh B.
I don't get it. One mesh has 24 points, the other 26. How can they be paired up?
--
David Rutten
david@mcneel.com
Added by David Rutten at 5:51am on December 27, 2013
rve
10 curve
11 curve
12 curve
13 curve
...and I'd like to rearrange the order in which the curve are listed, to something like this:
{0,0,0}
0 curve
1 curve
8 curve
9 curve
10 curve
11 curve
2 curve
3 curve
4 curve
5 curve
12 curve
13 curve
6 curve
7 curve
I hope this makes sense.
Thank in advance for any advice,
John…
この前のOpen fab nightで扱ったKangarooの日本語の解説が乗っているサイトがあります。興味ある方は参考にどうぞ
http://www.grasshopper3d.com/profiles/blogs/2985220:BlogPost:1222944?xg_source=activity