{1;1;4}{1;1;5}{1;2;0}{1;2;1}{1;2;2}{1;2;3}{1;2;4}{1;2;5}{1;3;0}{1;3;1}{1;3;2}{1;3;3}{1;3;4}{1;3;5}
etc...
and I want to format as a text it so it replaces the innermost branch with a letter so {0;0;1} would read A-0-1. I am able to replace all the symbols using replace text but am no sure if there's a way to convert a number to a letter.…
Added by Ryan Whitby at 12:40pm on February 3, 2015
{4}-0;3
{5}-6;7
{6}-5;7
{7}-5;6
Here it can be shown that there are two subgraphs containing 0,1,2,3,4 and 5,6,7. How can I use spiderweb (either using scripting or the components) to give me this result when I have many more vertices??
Thanks,
Sam…
rce',)Failed to copy the object. Returning the original objects...This can cause strange behaviour!Duplicate surface name! Name is changed to: Overhang (roof)_DupDuplicate surface name! Name is changed to: Adiabatic walls_DupDuplicate surface name! Name is changed to: Adiabatic walls_Dup_DupDuplicate surface name! Name is changed to: Adiabatic walls_Dup_Dup_DupDuplicate surface name! Name is changed to: Adiabatic walls_Dup_Dup_Dup_DupDuplicate surface name! Name is changed to: Adiabatic walls_Dup_Dup_Dup_Dup_DupDuplicate surface name! Name is changed to: Adiabatic walls_Dup_Dup_Dup_Dup_Dup_DupDuplicate surface name! Name is changed to: Adiabatic walls_Dup_Dup_Dup_Dup_Dup_Dup_Dup[1 of 7] Writing simulation parameters...Ground temperature data contains monthly average temperatures at 3 different depths .5 meters (1st)2 meters (2nd)4meters (3rd)respectively[2 of 6] No context surfaces...[3 of 6] Writing geometry...[4 of 6] Writing materials and constructions...[5 of 7] Writing schedules...[6 of 7] Writing loads and ideal air system...[7 of 7] Writing outputs......... idf file is successfully written to : c:\ladybug\unnamed\EnergyPlus\unnamed.idf
Analysis is running!...c:\ladybug\unnamed\EnergyPlus\eplusout.csv......
Done! Read below for errors and warnings:…
helped me solve some geometry problems).
I uninstalled energyPlus and installed again, updated the components, and hanges replaced the once that were not automatically replaced.And I have a deadline :(
Could it be because there are no materials assigned?
Thanks a lot.
Nita
p.s.
Analysis period is from 1 JUN to 31 DEC Between hours 1:00 to 24:00 Current document units is in Meters Conversion to Meters will be applied = 1.000 [1 of 7] Writing simulation parameters... Ground temperature data contains monthly average temperatures at 3 different depths .5 meters (1st)2 meters (2nd)4meters (3rd)respectively [2 of 6] No context surfaces... [3 of 6] Writing geometry... [4 of 6] Writing materials and constructions... [5 of 7] Writing schedules... [6 of 7] Writing loads and ideal air system... [7 of 7] Writing outputs... ... ... idf file is successfully written to : E:\Skins\PArametric_study\basecase\basecase\EnergyPlus\basecase.idf
Analysis is running!... E:\Skins\PArametric_study\basecase\basecase\EnergyPlus\eplusout.csv ... ...
Done! Read below for errors and warnings:
Empty…
Int32 = 0 To y.count - 1
Dim c As Char = Convert.ToChar(y(i).substring(7, 1))
Dim d As Char = Convert.ToChar(y(i).substring(8, 1))
Dim p As Integer
If c = ";" Then
p = convert.ToInt32(y(i).substring(6, 1))
Else If d = ";" Then
p = convert.ToInt32(y(i).substring(6, 2))
Else
p = convert.ToInt32(y(i).substring(6, 3))
End If
Dim path As New EH_Path(p)
For j As int32 = sum To sum + z(i) - 1
tree.Add(x(j), path)
Next
sum = sum + z(i)
Next
A = tree…
o relate to each plane its sections i.e.:
paths=624 - {0;0;2;0}(N=1)
the number of section planes is 70 and somewhere I have 4 section lines and somewhere 5 or 8, is it clear?
1 plane = 1 set of sections
thank you for helping me.…
Added by paul piciorul at 5:35am on October 28, 2010
;-2;-1;0;1;2;3) and beside that i don't want to have 0 as a result.
So at the End I would like to have only 6 numbers: -3;-2;-1;1;2;3
I already came to an result with integer numbers but it actually only rounded up the random results. when one of the results was -0.473 it ended up as 0.
I'm sure it's pretty easy to solve, I'm just missing something.
thx for help…
91 Items on 13 Branches (7 rows * 13 columns = 91 points)
Path Structure is:
The Address of all those items on the Data Tree.
Think of the "{0;0;0}" format as an addressing system.
The not obviously necessary extra 0's at this point represent the equivalent to Country and State (or something like that)
So the first point in your grid in Column 0 Row 0 has the address {0;0;0}(0)
The next point up is {0;0;0}(1) until you get to the to of the column {0;0;0}(6)
The Next column over is {0;0;1} with points ranging from (0) to (6)
We continue like this until we get to the last column Last Point {0;0;12}(6)
Therefore a relative path from the first point in the first column to the last point in the last column is {0;0;+12}(+6}
Does this make sense so far?…