this doesn't make any sense... but the Data Log component for Firefly does essentially what the Data Recorder now does (although the Data Recorder is much more compact)... The only difference is that there is a Wrap input which would create the list as above.…
oning behind using the equality component to test for even numbers is flawed because of the data matching used by gh. It is testing like this:
0==0 True
2==1 False
4==2 False
6==3 False
etc
.............
Where as a Modulo 2 would work like this
0%2 = 0
1%2 = 1
2%2 = 0
3%2 = 1
4%2 = 0
5%2 = 1
6%2 = 0
7%2 = 1
8%2 = 0
9%2 = 1
......
Also I notice you have some errors in your expressions producing Nulls.
If you want it to be twice the value then you should have 2*D in the Expression and 10*D in the other
....
I attach a working version.…
to install parallels and Windows 7 (I've read to get Windows 7 for now not 8) and use my Rhino 4 (got this a while ago and haven't used it yet due to I'm on a mac). The macbook has 16gb RAM so I could allocate 8 to Windows side and load Rhino 4 or upgrade to Rhino 5 but want to be sure Grasshopper will run or I'll do the Bootcamp thing and sacrifice the restart every time I use Rhino/Grasshopper. I'm just starting this Grasshopper road so zero experience. First thing is get the system right (for me who uses mac.s). I've heard Rhino 4 and 5 will run okay on parallels with Windows 7.
Thanks…
ements between mid axes of elements ( being perpendicular to both). On the attached image, the links are the small elements connectiong nodes 4 to 5, 6 to 7 and 8 to 9. All nodes (1 to 9 including 1', 2', 3') are defined in Karamba as fixed supports but nodes 1,1', 2, 2', 3, and 3' have hinges added with the beam joint component. The freed rotations are shown on the figure.
I wondered if that was the correct way of defining such a structure in Karamba bearing in mind that nodes 1', 2' and3' are free nodes in the reality.
Thanks again for your help !
Yousef…
vector * number
8. number * point
9. point * number
10. complex * complex
11. colour * colour
12. colour * number
13. number * colour
--
David Rutten
david@mcneel.com
Seattle, WA…
Added by David Rutten at 10:39pm on November 12, 2010
4 to 9
Is there a way to do this with the list or sequence components other than retrieving individual list items and then lofting between each list item (circle). There must be a more elegant way to do this.
Thanks very much.
please see the attached definition as a sample...…
of the intersection points is giving me some problem.
Here is the process i've done to come up with the grid (best viewing the image!):
1. create a base rectangular polygon;
2. find the diagonals and subdivide these, let's say in 10 points;
3. connect the points of one diagonal to the adjacent one in this order:
1 to 9
2 to 8
3 to 7
4 to 6
5 to 5
6 to 4
7 to 3
8 to 2
9 to 1
4. find the intersection points on every line drawn.
Now I would like to create individual surfaces connecting all the points that form the vertices of the polygons, but I cannot find out how...
Can somebody help me?
Thanks so much!…