as follows.
We have a grid which consists of a collection of columns, where each column consists of a list of points. You said flattening is out of the question, so we need to cull items from each list individually.
Let's say our culling pattern is KDDDKDD (repeat as needed). K = Keep, D = Ditch. If a column contains 18 points, the pattern needs to be repeated until it is 18 items long. In this case:
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18
K D D D K D D K D D D K D D K D D D
We can now cull each column, but they will all be culled in the same way. By shifting the pattern one more index for each column, we can cycle the culling.
The fix incidentally is to Shift the pattern PRIOR to repeating it. Then it works as expected:
--
David Rutten
david@mcneel.com
Tirol, Austria…
Added by David Rutten at 2:49pm on October 2, 2013
tivas.
Desde lo básico a sistemas complejos + documentación para fabricación.
Orientado a Diseñadores, Arquitectos, Artistas Multimedios y profesionales afines.
Objetivos específicos:
• Distinguir los conceptos principales del diseño paramétrico y su aplicación en entornos de modelación CAD. • Manejar la modelación paramétrica de sistemas geométricos simples y complejos en Grasshopper 3D. • Aplicar el conocimiento paramétrico en la creación de documentación para construcción y fabricación de un modelo desarrollado en Grasshopper 3D. Contenidos: Sesión 1. Introducción a la modelación paramétrica. Sesión 2. Elementos geométricos y sus propiedades. Sesión 3. Estructura de la información. Sesión 4. Condiciones de campos, grillas y atractores. Sesión 5. Panelización de elementos en superficie complejas. Sesión 6. Parametrización orientada a objetos. Sesión 7. Documentación paramétrica 1. Sesión 8. Documentación paramétrica 2. Sesión 9. Modelación avanzada y optimizaciones. Sesión 10. Profundización personal.
Fechas : Del 14 de Marzo al 13 de Abril de 2016
Modalidad : Presencial
Duración : 30 horas (10 sesiones)
Horario : Lunes y miércoles de 18:30 a 21:30 hrs.
Facultad : Escuela de Arquitectura
Pontificia Universidad Católica de Chile
…
iseño de proyectos a través de algoritmos mediante programación. Se explica el entorno de Grasshopper, se desarrollan diversos ejercicios. No es necesario conocimiento previo de Rhinoceros ni de programación.Total horas: 20 hrsFechas, Horario, Sede: Revisar la página de "Próxima Formación"Otros beneficios: 1) Un CD con: libreria de definiciones de Grasshopper desde herramientas simples hasta complejas y libros, tutoriales relacionados.2) 10% de descuento en los siguientes cursos o talleres que SEED | KRFR organicen.3) Posibilidad de unirte a SEED y a KRFR para hacer prácticas o para generar proyectos en conjunto.4) Se da un 10% de descuento en el licencia original de Rhinoceros.…
Added by ESTUDIO SEED at 2:41pm on January 17, 2011
ap value = True
Shift List = 1 --> (B,C,D,A)
Shift List = 2 --> (C,D,A,B)
You can also use negative values.
Shift List = -1 --> (A,B,C)
Shift List = -2 --> (A,B)
and with Wrap = True
Shift List = -1 --> (D,A,B,C)
Shift List = -2 --> (C,D,A,B)
The most useful Shift List action I use is to either get rid of the first or last item in a list and sometimes both.
Shift list = -1 --> (A,B,C) Shift list = 1 --> (B,C)
In the example posted above you are creating a shift list value equal to its location along the curve. The first section = 0 doesn't get shifted, the second section gets a shift = 1, third = 2, forth = 3 and because the wrap value is set to true the fifth section gets back to 0, sixth = 1 etc etc. creating the twisting effect.
The "one more stupid question" answer is Mass Addition. You will find the component on the Math tab or you can type it into the Keyword search feature (by double clicking the canvas). This component has two outputs a total amount for each list and a partial set of results giving:
List (3,6,9,12)
{0} = 3
{1} = 3+6 = 9
{2} = 3+6+9 = 18
{3} = 3+6+9+12 = 30…
introduction to Arup parametric work (10 mins) and a brief description of Gifu Library by Toyo Ito.
Paul Jeffries on Arup developed tools including StaG, Salamander and the KTC workflow. (10 mins)
Vladimir Marinov on parametric optimisation of curved glass (10 mins)
Clayton Riddle on his work in Australia (10 mins)
And we will have two external speakers on the night.
Stephen Melville + Will Pearson (Format - RCD) on Daniel Liebskind's Milan Expo Pavilion (20 mins)
Loop.Ph (Mathias Gmachl and Rachel Wingfield), Latest Work. (20 mins)
Please feel to invite other colleagues and collaborators. Refreshments will be provided.
See you very soon,
Toby, Paul and Arthur …
ossibilities. Aimed at those with little or no prior experience, this class will cover all the essentials needed to quickly get started :
• Basic Interface - how Grasshopper works • together with Rhino • Creating and manipulating all the main • geometry types - Points, Vectors, Lines, • Curves, Surfaces and Meshes. • Organizing data with Lists and Trees • Using simple Mathematical and Logical • expressions • Extracting information for fabrication • Tips, tricks and shortcuts • Common pitfalls and how to avoid them • An introduction to physical simulation • with Kangaroo…
Added by Paul Cowell at 5:08pm on September 22, 2012
(18, 11, 0, 17), also put in the assembly component.
How can I know which value of the reaction forces correspond to which support?
In the manual is stated that when the reaction force component is used, than the values are displayed in ascending sequence of the corresponding nodes.So if I input the support nodes like thispoint with index 18point with index 11point with index 0point with index 17are the reaction forces displayed like this (per loadcase)?0 - reaction forces in point with index 01 - reaction forces in point with index 112 - reaction forces in point with index 183 - reaction forces in point with index 17
Thanks!
BestLara…