ld go
Slider at 1 -> 1°, 2°, 3°.
Slider at 2 -> 2°, 4°, 6°
Slider at 3, etc.
And when the angle was too much that it surpassed 90 before connecting the 20 points, that line was not created. Maybe using a series instead of a range...mmm
Everything helps, thanks
…
t incremental numbers, rather than showing the slider values.
Also please note that it will iterate over all possible slider values, so if you have 6 sliders that go from 0.0 to 10.0 with 3 decimal places, then you'll have to wait for (10x1000)6 = 1 septillion solutions.
--
David Rutten
david@mcneel.com…
Added by David Rutten at 1:37pm on November 23, 2013
a specific location. In this case, it refers to the numbers that are part of a data-tree path list. For example, the path {0;0;3} has 3 loci. The path {0;0;3;1;2;6} has six loci. When you want to flip a data-tree using Flip Matrix, then all the paths can only differ at a single locus, thus:
{0;0;0}
{0;0;1}
{0;0;2}
{0;0;3}
is fine because only the third locus differs. If the tree is more complex:
{0;0;0}
{0;0;1}
{0;1;0}
{0;1;1}
then Flip Matrix doesn't understand which rows and columns to flip.
You'll have to use a Path Mapper to solve this problem I think.
--
David Rutten
david@mcneel.com
Tirol, Austria…
Added by David Rutten at 4:46pm on October 8, 2013
}
0,3
{7}
1,2
{8}
1,3
{9}
2,3
{10}
0,1,2
{11}
0,1,3
{12}
0,2,3
{13}
1,2,3
{14}
0,1,2,3
I want it to be parametric so I can have it for any set of indexes
I have tried to solve it with points and then removing duplicate points but it's not helping much
any help is truly appreciated
…
s {0} with 0/1/2 and the values 1/1/1
{1} with 0/1/2 and the values 2/2/2
{2} with 0/1/2 and the values 3/3/3
Second data set contains 3 items {0} with 0/1/2 and the values A/A/A
{1} with 0/1/2 and the values B/B/B
{2} with 0/1/2 and the values C/C/C
After merging the 2 data sets i need as result one data set with 6 items {0} with 0/1/2 and the values 1/1/1
{1} with 0/1/2 and the values 2/2/2
{2} with 0/1/2 and the values 3/3/3
{3} with 0/1/2 and the values A/A/A
{4} with 0/1/2 and the values B/B/B
{5} with 0/1/2 and the values C/C/C
How can i realise this?…
13 5 15 6 17 7 ... …
But it seems I have not been clear:
the input values (3,5,7,9,11,13) should be presented in the way of "number slider" parameter. So by increasing the value of the slider from minimum 3, to 5, 7, 9, 13, 15, 17... I should get an output numbers of 0,1,3,4,5,6,7...
So I if choose value 3 on the input "number slider", on the other end, I want 0 as an output.
Or if I choose value 5 on the input "number slider", I want 1 as an output, and so on.
Is this possible?…
onsecutive points at the same height then your 'Break at discontinuities' component eliminates the middle point completely and then the 'Interpolate Curve' component gives a much bigger bump in the wrong direction. This was enough to get curves to meet from opposite sides.
I fixed this by changing the heights to 1.1 or 2.9, rather than 1.0 and 3.0, but it took a little while to work it out! Sigh.
I attach a new version. But I actually preferred it as it was before. See what you think!
Bob
p.s. in the first list, elements 11, 12, 23 and 24 go from 1 to 3; elements 17 and 18 go from 3 to 1. In the second list, elements 6, 17, 18 and 29 go from 1 to 3; elements 12 and 23 go from 3 to 1. Given the above fix, these can be easily seen.…
Added by Bob Mackay at 10:40pm on November 24, 2015
al vector.
4. Create a Line SDL using the centroid and vector as inputs, make it relatively short.
5. Move it "backwards" (the oppesite direction of the normal) by half the length, so as to place it in the middle of the surface.
6. Carry out the intersection check!
/T…