, so using distance to centre point, you can give all the useless values a 1. Cutting down the values you actually need to work out by 80%. Which is helpful when approaching 1 million points.…
t it is rounded to 25, 100, 75. I've figured out the rounding portion, but when I plug the resulting list back into the custom preview, it doesn't recognize the data. I'm guessing it is because my rounded list is in curly brackets, whereas the unrounded data straight from the image sampler is not. How can I process this to remove the curly brackets?
Thanks,
Ryan
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Added by Ryan Dirks at 5:20pm on September 18, 2014
is allowed to be increased, depending on the air speed as specified in Table 5.4.2.4, which can be as high as 2.2 degree.
So, I assume the height of the "hump" is about 2.2 degrees from the upper acceptability limit (80% or 90%).
Appreciate your advice if the understanding here is not correct.
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"surfaces" ? Our teacher said to place the truncation according to this relation : Capture%20d%E2%80%99%C3%A9cran%202016-05-01%20%C3%A0%2008.03.46.png I already make the five platonic polyhedrons in Rhino.
Best,
Nastia …
18): 'Rhino.Geometry.AnnotationBase.Text' is obsolete: 'Use RichText or PlainText' (line 88)
2. Warning (CS0618): 'Rhino.Geometry.AnnotationBase.FontIndex' is obsolete: 'Use Font property instead' (line 92)
3. Warning (CS0618): 'Rhino.RhinoDoc.Fonts' is obsolete: 'Use DimStyles table instead' (line 92)
1. Error (CS1061): 'Rhino.Geometry.TextEntity' does not contain a definition for 'AnnotativeScalingEnabled' and no extension method 'AnnotativeScalingEnabled' accepting a first argument of type 'Rhino.Geometry.TextEntity' could be found (are you missing a using directive or an assembly reference?) (line 94)
Wondering, if perhaps, you will be updating for Rhino 6 compatibility?
Cheers
Lyndon
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the only thing that i have to fix is to make the holes appear semi-random. At for example at 30% - 80% of the height, or between fixed heights.Thanks again for your effort.…
7,8. It would plot on the line of the 20%, 20%, 70%, 80% of the length of the line. I'm not looking for a way to divide the curve by 2 and then by 2,not steps. So I would have two points at 20%. I hope this is clear.
Thanks,
Tom…