he contents to e.g. d:\test.csv
To draw in processing should be something like this (untested code, I don't have processing at this moment):
Table table = loadTable("D:\test.csv");println(table.getRowCount() + " total rows in table"); for (TableRow row : table.rows()) { line(row.GetFloat(0),row.GetFloat(1),row.GetFloat(2),row.GetFloat(3));}
…
actually in position 3)
Weave is useful when you have two lists with several objects in each, and you want to combine them into one list, in a particular order (that order being the "Pattern")
So if you have a list with letters: A, B, C, D, E, F... into input 1
And a list of numbers: 1, 2, 3, 4, 5... into input 2
With the pattern: 1, 1, 2
The output of the weave would be A, B, 1, C, D, 2, E, F, 3...
Until it runs out of list.
Hope that helped!
john…
nded from the centerline at a specified thickness, which may vary along the stent.Two parameters, tmid and tend, control thickness variation
along the segment’s longitudinal direction according to the kinematically admissible Hermitian
curve:
t (d) = tend + t(3d2 − 2d3) 0 ≤ d ≤ 1
t = tmid − tend
where d is the normalized distance along the segment’s
NURBS curve between its endpoint and midpoint. This
form ensures there are no discontinuities in thickness at
the segment midpoint or at the interface of segments in the
overall stent.
2)These normals are then checked and subject to a filleting
procedure to remove re-entrant corners, resulting in
two external sets of boundary coordinates defining the
external edges of the segment’s mid-plane.
3) This plane of nodes is then extruded at a specified angle
(see Section 2.3) to generate a 3-D set of nodes defining
the finite element mesh.
4) These nodes are then mapped to cylindrical coordinates.
5) Finally, 20-node brick elements are generated for finite
element analysis.
I have generated the centerline using 8 control points with degree 7 .
Would be great if anyone can help me with the drawing the normals from the centerline of specified length governed by Hermitian equation,so as to generate the 2D model of a stent (Please refer to the attached figure of a 2D stent and extruded figure) ,using Grasshopper.
The centerline of a single stent segment is representedas a NURBS curve.…
explode curves the data is (0;0;0;0)....(0;2;0;383) and here Arthur Mamou used Path mapper or flip matrix but no one of this solutions is posible in this case because: path mapper extracts (A;B;C;D) and we have items on (A;B;C;D), and flip matrix doesnt work... I have create a subset of list N=4 to get a list with the points of the spheres and flip the matrix to get four branches in order to get the points to input in the pressure force. Sorry but i´m not a teacher and there is, for sure, a better way to do it. Cheers. ; )…
Added by lucas cañada at 4:41pm on January 9, 2013
, E, H, C, F, I
So instead of Weave component, you might want to use the "Merge 03" component. It merges 3 data lists into one sequentially. For the example above, you would have:
A, B, C, D, E, F, G, H, I
Hope this help.…
Added by June-Hao Hou at 7:30am on December 4, 2010
ep (brerp width = 1 unit)
i = 10
According to the following logic
IF A
A: C or A (random select)
B: C or A (random select)
C: D or B (random select)
D: B or D (random select)
Than choose c or A
Choose randomly the module C or A and move of 2 units (i)
Than
If C, choose D or B and move of 3 units
If A, choose C or A and move of 3 units
Than
any help appreciated
thanks
s…