rcle A 0---1---2Circle B 0---1---2---3---4---5---6---7---8---9---10---11I was actually trying to connect through separated lines, point (A,0) to (B,11) and (B,1),point (A,1) to point (B,3) and (B,5), and (A,2) to (B,7) and (B,9).I was able to do it using a list item selecting the points and creating a line between them, but i would be to long to do it if i would like to divide in many more points, and try to connect them using list item... i went looking around for a bit, i think its possible to do it with a path mapper or a flip matrix, althought i have no clue how to make it.
You will find enclosed, some screenshots...If anyone could give me any tip, i thank you all in advance.Have a nice day.+Joan…
Added by Joan tarragon at 7:38am on December 5, 2011
cy they don't get shown.
You can display them but you will have to pass them through an [Expression] or a [Format] Component, where R is a real number
{0:0.000000000} would set it to display 9 decimal places
{0:0.000###} would be 3 decimal places but 6 where significant
{0:0} would be an integer…
Added by Danny Boyes at 8:59am on November 11, 2013
1) to each length. For example you have a length of ten and you create a domain from 9 to 11. later you want to group all lines by as less as possible domains.
If you have a look to the image...you see 6 lines and their red dotted ranges. to group them by the domain of 3 and 5 would be the best result with the less domains. (here 2)
if you would use the domain of line 0,1 or 3 you could not include line 4 and you would have 3 instead of just 2 groups.....
later on it is important for me to group as much as possible lines in less as possible domains.
I hope this is somehow understandable.…
Added by horst Becker at 11:15am on November 2, 2013
of the intersection points is giving me some problem.
Here is the process i've done to come up with the grid (best viewing the image!):
1. create a base rectangular polygon;
2. find the diagonals and subdivide these, let's say in 10 points;
3. connect the points of one diagonal to the adjacent one in this order:
1 to 9
2 to 8
3 to 7
4 to 6
5 to 5
6 to 4
7 to 3
8 to 2
9 to 1
4. find the intersection points on every line drawn.
Now I would like to create individual surfaces connecting all the points that form the vertices of the polygons, but I cannot find out how...
Can somebody help me?
Thanks so much!…
ation 2 Elements : 750 combinations 3 Elements : 187500 combinations 4 Elements : 23484375 combinations 5 Elements : 1769539000 combinations...
Even if you get all combinations with a magic zero-time-algorithm it's nearly impossible to store them or apply functions on them.…
d) .
That said since a mesh consists from 3 types of objects (vertices, edges and faces) there's 9 possible connectivity possibilities.
BTW: for 2 given Lists of items a connectivity tree samples integers in branches where the primary dimension is the item's index in List A and the items are indices in List B.…
e a list of coordinates which I need to sort in groups as per a series of numbers in another list. Both are txt files which I'm reading to bring a series of points in but those points are generated with a corresponding index.
Of course the lists are not sorted in any way, but the numbers are corresponding so it looks like a series of 9, 6, 7, 2, 8, 0, 9, 5, 6, 4, 2, 3, 8, 5, 5, 6, 9, 4 in one file( and series of (X, Y, Z) coordinates in the other.
The question is how can I make it to sort the list and then split it per index... if it is possible... or should I just do this in excel and bring clean lists in?
My idea, if it works, is use the series of points to generate paths and work with them.
I'll attach the lists just if it helps making a clear idea.
Any advice will be very welcome.…
1th of summer is ok but the other is unnatural.
my window contains louver
the 3th is analysed with a sky with 10000 lux iluminance. this is natural too
could anybody guide me please... which one is correct…
the shorter one) rotates in one direction about a fixed point. This rotation is generally limited to 0-180 degrees. The longer segment can rotate freely at the "elbow" (like a socket joint). All 3 arms converge at a single point (where an end effector would be). To generate this point I referenced a curve from rhino and I move the point along the curve in grasshopper.
I did it in 9 components (including the method of creating the point on the curve and piping the lines at the end).
The length/sizes of your arms can be whatever you would like. Just for reference my short segments are 1.5 inches and long segments are 3 inches.
Rules are that it must be GH native with no scripting. Deadline is monday the 26th at midnight (pacific time).
let me know if you have any questions!…