thing deeper? ".. these and then some more.
As this simple search in the source code will tell you, right now at least Honeybee is meant to be run on Windows. There is a cross-platform version already in the works which will run seamlessly across different platforms.
Sarith
(I don't know if what I said above applies to Ladybug as well as I am not involved in that project).…
other notation... where x, y and z are variables, and a,b,c... are constants but sliders, open for dynamic change. + Defining its interval.
- Another minor question; the intcrv box, it is by default a polynomial interpolation? In general, where can you get information on the underlying math behind the boxes?
- Is it possible to define the intervals on the sliders based on other sliders or inputs?
Many questions, but I have been trying to figure this out for quite some time now. I am truly grateful for all help on this matter! :) Maybe they will be of help to other engineers or architects out there...
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blinds be (B1,B2..B5). Then the geometry for the five iterations will be ((A+B1), (A+B2)...(A+B5)).
And assume that you are measuring illuminance at four points inside the room (x1,x2,x3,x4) and one point outside the room(y1).
The way Daysim works ( and should work as per the best of my understanding) is that for each setting of the blind (ie. B1,B2,..B5), a separate value of (x1,x2,x3,x4) gets calculated through the Daylight Coefficient Method. So let's say you have illuminance thresholds of (p,q,r,s,t) corresponding to (B1,B2,..B5). What the shade-control algorithm does is that it compares the illuminance at y1 with your threshold of (p,q,..t) and then chooses a value of (x1,x,2,x3,x4) on basis of that. So, when we repeat this process for (365x24=)8760 hours , we end up with a value of a shade setting for each hour which was set on basis of your threshold illuminance values.
I would have gladly answered your question on HB itself, however, I usually work with Daysim directly through commandline.
(BTW, if you are interested in reading more about Daysim google Christoph Reinhart's dissertation on the subject, along with some papers by Zack Rogers).…
rees west to 1 degree west). Changing the latitudinal domain from, say, 0:1 (the equator to 1 degree north) to 88:89 (88 degrees north to 89 degrees north), has zero effect on the x,y shape of the topography map generated. However, in reality, the map should be far, far thinner in the latter case, because longitudinal lines get closer together toward the north and south poles. In actuality, the shape should be close to a trapezoid in both cases, but this is probably not a necessary detail for most people producing maps, since, at an urban or smaller scale, the latitudinal lines bounding the north and south of the map will probably not be that significantly different in length. But the maps should at least stretch from close-to-square for a 1 degree x 1 degree map near the equator to an extremely thin rectangle for a 1 degree x 1 degree map near the north pole.
As an example, I'm looking at a location in Sheffield, UK. The relevant SRTM HGT file spans from 53 N to 54 N, and 2 W to 1 W. The length of the map in the north-south direction should be approximately 111 km, as is the case with the topo map generated by Elk (and a near-standard for 1 degree latitude anywhere in the world). The length of the map in the east-west direction, however, should be somewhere in the range of 67 km, since the 2 W and 1 W longitudinal lines are much closer together at this latitude than they are at the equator. Thus the map should be nearly twice as long in the North-South direction as it is wide in the East-West direction.
If this were to be sorted out, I think it would be really nice to then have the SRTM topo map be positioned automatically in relation to the OSM map being brought in. I think it's good that the OSM map is positioned at 0,0, rather than it's world coordinates, but maybe the SRTM topo map could be aligned with it based on the latitude and longitude domains we input to the SRTM grasshopper module.…
behave like this:{a1;b2;c3;d1;e2;f3;g1;h2}
The ping pong matching would behave like this:
{a1;b2;c3;d2;e1;f2;g3;h2}
with a boolean option it could repeat the first and last like this:
{a1;b2;c3;d3;e2;f1;g1;h2}
If this already exist please let me know
Thanks
bye…
Added by Frane Zilic at 10:15pm on August 19, 2012