byte-accuracy red, green, blue channels) = 27 bytes. More likely 28 bytes as colours are probably stored as 32-bit integers, allowing for an unused alpha channel.
28 * 800,000 equals roughly 22 megabytes, which is way down from 9 gigabytes. That's a 400 fold memory overhead, which is pretty hefty.
Grasshopper stores points as instances of classes, so on 64-bit systems it actually takes 64+64+3*8 = 152 bytes per point*, which adds up to 122MB, still way less than 9GB. It would be interesting to know where all the memory goes...
* Grasshopper points also store reference data, in case they come from the Rhino document. This data will not exist, but even so it will require 64-bits of storage.…
Added by David Rutten at 4:13pm on December 11, 2014
e possible to change the component definition making possible to customize the number of outputs.Now Dispatch moves "true" values to A and "False" values to B
INPUT:
L (List to work on) -> 1, 2, 3, 4, 5, 6, 7, 8
D (Dispatch Pattern) -> True, False
OUTPUT:
A (List) -> 1, 3, 5, 7
B (List) -> 2, 4, 6, 8
Could it be possible/useful to modify it so it could dispatch items to several outputs, like:
INPUT:
L (List to work on) -> 1, 2, 3, 4, 5, 6, 7, 8, 9, 0
D (Dispatch Pattern) -> A, B, C
OUTPUT:
A (List) -> 1, 4, 7, 0
B (List) -> 2, 5, 8
C (List) -> 3, 6, 9
maybe I'm missing something and there's already a component with this function... I have been searching on the forum for half afternoon, but can't find anything about it!
Thank you!…
en 3 of them, and one poolyline between two of them.
It would also be very nice if i could control it so that only the successive ones can be connected
so if {0:0:0} has 8 points and {0:0:1} has 8, as do {0:0:5} and {0:0:6} i would like to have this as two polylines, not one continoous that would in this case jump three branches (or curves that are shorter).
Does this make any sense?…
Added by Dusan Bosnjak at 2:08pm on September 28, 2009
10 from the other list and insert/splice them into the original list (at the specified index, not appended to the list end) while overwriting the values contained therein- how would I go about this task? Ideally, I could then, in a second step, take yet another range of indices (20, 22.. whatever) from another list and splice them in again.
Any thoughts?
Thanks & g'nite
Max…
a follow up question... how do I wrap a list onto itself at a certain frequency?
i.e. I want the list {1;2;3;4;5;6;7;8;9}
to become {1,4,7; 2,6,8; 3,6,9} wrapped every 3rd item
Added by Joshua Jordan at 5:30pm on November 17, 2012
an = True
For j As Integer = i + 1 To x.Count - 1
If round((x(i).x * 10 ^ 8 + x(i).y * 10 ^ 4 + x(i).z), 2) = round((x(j).x * 10 ^ 8 + x(j).y * 10 ^ 4 + x(j).z), 2) Then bol = False
Next
If bol Then ptlist.add(x(i))
Next
a = ptlist
I think someone posted a more appropiate way of doing it, similar to how the "seldup" command works. You can also run the seldup command in a script using app.RunScript("-seldup"), but its a bit messy since you have to bake the geometry first and select the resulting geometry all within the script.…