;-2;-1;0;1;2;3) and beside that i don't want to have 0 as a result.
So at the End I would like to have only 6 numbers: -3;-2;-1;1;2;3
I already came to an result with integer numbers but it actually only rounded up the random results. when one of the results was -0.473 it ended up as 0.
I'm sure it's pretty easy to solve, I'm just missing something.
thx for help…
I believe in the help under export to AI it describes the specifics of exporting to AI, such as curves must be in degree 3 or >3. At degree 2 it's not as accurate
output: 0, 1, 3, 6, 10, 14, 17I have a basic understanding of programming and can understand vb.net better than I can write it. Any help would be greatly appreciated!ThanksJeff…
ep is to understan the logics of what you want to do, in your case, build 4 point surfaces (u also need to know the right direction to build the surfaces). Then you can write an hipotetic list (by hand in a paper) of what you want. In your case the list was (0, 1, 3, 2) (2, 3, 5, 4) (4, 5, 7, 6), etc... if you can imagine building 2 lists, each one with the sequences (0, 2, 4, 6, etcc) and (1, 3, 5, 7, etc..) then you can manage with shift and graft to finally have four lists. A( 0 1 2 3 ...) B (1 3 5 etc..) C(3 5 7 etc..) D (2 4 6 etc..). And to achieve the 2 first lists, you need to get the odd and the pair numbers. The cull pattern does that amazingy well. With a pattern True-False you get de pair numbers, and with the False-True pattern you get de odd numbers.
Hope it was clear enough…
Added by Pep Tornabell at 5:32am on November 19, 2009
}
X*
{0;2;0}{0;2;1}{0;2;2}{0;2;3}
{0;3;0}{0;3;1}{0;3;2}{0;3;3}
And now we want to insert at the place marked with X* another list formated like:
{0;0}{0;1}{0;2}{0;3}
So we want it resulted like:
{0;0;0}{0;0;1}{0;0;2}{0;0;3}
{0;1;0}{0;1;1}{0;1;2}{0;1;3}
*{0;2;0}{0;2;1}{0;2;2}{0;2;3}* - the inserted list
{0;3;0}{0;3;1}{0;3;2}{0;3;3}
{0;4;0}{0;4;1}{0;4;2}{0;4;3}
Since we plug the list formated with only {A;B} into the place with has {A;B;C} then that list has to be reformated in the same manner and every lists which are next to it have to be reformated too by adding 1 to B so it's {A;B+1;C}.
Param viewer with the data tree diagram is a great tool for visualising data structure. It seems to me that it would be easier to play with lists in the same way as we do with connecting components together. So if we have list of points and we want to insert them at some certain place in the tree then we don't need to play with Patch Mapper, Insert List and others but we just plug them on one go into the tree and format will adopt itself automaticly according to the choicen position on the tree.
Same with OUTPUT. We can pick some elements from the tree and connect it to the component which will receive every element from that branch. (example):There is a list of points with complex data structure. we pick node {0;0;3} and move it out from param viewer to connect it with point component which will receive all the sublists with elements which are under it:
{0;0;3;0}0 - pt1 - pt2 - pt{0;0;3;1}0 -pt1 - pt2 - pt3 - pt...and so on...
I don't know if this solution make better sense then other solutions of this case. Maybe there are easier ways to do it without such complication and I have no idea about it :)
greets!
Adam
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