}
0,3
{7}
1,2
{8}
1,3
{9}
2,3
{10}
0,1,2
{11}
0,1,3
{12}
0,2,3
{13}
1,2,3
{14}
0,1,2,3
I want it to be parametric so I can have it for any set of indexes
I have tried to solve it with points and then removing duplicate points but it's not helping much
any help is truly appreciated
…
imilar topic with a Windows 10 user, which successfully fixed this issue.If you are tiny little patient, I think we can try the same steps in your Windows 7 case.For start, try these three steps:1) Close Rhino. Restart your PC. 2) Once the PC boots up, double click on the "regMapWinGIS.cmd" file in "MapWinGIS" installation folder.3) When it closes the Command Prompt window it opened, try running Rhino, Grasshopper and drop the "Gismo Gismo" component on the canvas (Grasshopper working area).If this does not help (you get the same COM class factory CLSID error message coming out from the "Gismo Gismo" component), then try the following steps, one by one:
1) Close Grasshopper and Rhino2) Run the Revo Uninstaller Pro and uninstall your MapWinGIS application along with removing all the leftovers from the registry. You can download 30 days trial version of it from here. Here is a youtube example of a bit older Revo Uninstaller. But the important part is that is shows how registry leftovers are removed.3) Restart your PC, and once it boots again, make sure that you are logged in as an Adminstrator!4) In your Start menu's search box type: "UAC", which will find your User Account Control Settings. Click on it, and a new window will open. Set the bar on the left to "Never notify".5) Turn off your Antivirus, which ever it is.6) Download the 64 bit version of v4.9.4.2 MapWinGIS.7) Right click on downloaded MapWinGIS-only-v4.9.4.2-x64.exe file, and choose "Properties". If there is "Unblock" button click on it, and then click on "OK". If there is no "Unblock" button, just click on "OK".8) Left double click on MapWinGIS-only-v4.9.4.2-x64.exe file and install it to "C:\dev\MapWinGIS" folder. Choose "Full installation" during installation process!9) In your Start menu's search box type: "CMD". Once the "Command prompt" appears do not left click on it! Instead right click on it, and choose "Run as Administrator".10) A command prompt window will open. Type the following command:
"your_regsvr32_folder_path\regsvr32.exe" /u /s c:\dev\mapwingis\mapwingis.ocx
If command does not result in an error message, then type this one afterwards:
"your_regsvr32_folder_path\regsvr32.exe" /s c:\dev\mapwingis\mapwingis.ocx
11) If no error appeared again, then open your Rhino and Grasshopper and check what "Gismo Gismo" component prints from its "readMe!" output.If errors appeared, please post their screenshots. Thank you in advance.
Please accept my apologies for the large number of steps. Some of them are quite simple actually (click on this, download that...).…
Added by djordje to Gismo at 12:58pm on November 28, 2017
this, you'll have no horizontal force at the roller, but you will have it at the pinned support. If you wouldn't, then the structure will be displaced.
Usually, in 2 dimensional structures, if you want to know if an articulated structure is isostatic (as opposed to hyperstatic, which is what you have right now) is to use the following formula:
b+c-2·n=0;
b being the number of bars, c the number of constraints you have and n the number of nodes. In your case: b=19, c=3 (displacements constrained in X, Z at your pinned support and only constrained in Z at your roller support) and n=11, so: 19+3-2·11=0.
I recommend you to download the app SW Truss, as it's very useful to check your results instantly.…
the catenary shape
6) Get the mid point of all the heaxgons
7) Create surfaces to get the average normal of each hexagons
8) Project the hexagon on the normal plane
9) Move the plane using the normals
10) create mesh faces between first and second hexagons
11) create mesh faces to close the planar hexagon
12) Orient all the mesh faces on a flat grid to laser cut them
13) Join and weld the mesh
14) Thicken the mesh using Weaverbird to get a shell
I hope this helps. It is all one mesh at the end made of quads on the side and triangles on the top (yes 6 of them).
All the best,
Arthur
…
not sure about my method used to obtain the result.I think is really complex; do you know a smart method to simplify all my equation?
thanks guys!! :D…
asuring Urbanity."
The seminar aims at re-centering the debate of measuring urban form on the contemporary issues of designing, planning and regulating the extensive city. It will bring together a group of international experts on the subject and the objective is to discuss the importance of combined qualitative-quantitative approaches on the generation of new insights on the contemporary urban environment and planning strategies.
The workshop presents a set of innovative approaches and methodologies using its own software. At the workshop participants will be invited to use the available toolset to address a specific urban issue where the construction of models for automatic measurement of urban indicators will be part of the urban design process.The workshop is intended for all urban planning professionals who want to improve their skills and knowledge as well as for students or doctoral students in urban planning. The CIAUD will issue a participation certificate equivalent to 3 ECTS credits.The workshop will run from 7 to 12 May 2012 and the seminar will be held on May 11, 2012 in FAUTL.The seminar and workshop program can be found attached ora t the website: http://www.measurb.org/en/home.html We thank in advance for the dissemination of this event to whom might be interested.
Best regards
José Beirão
Cristina Cavaco
workshop.pdf
seminar.pdf
Measuring urbanity…
rcle A 0---1---2Circle B 0---1---2---3---4---5---6---7---8---9---10---11I was actually trying to connect through separated lines, point (A,0) to (B,11) and (B,1),point (A,1) to point (B,3) and (B,5), and (A,2) to (B,7) and (B,9).I was able to do it using a list item selecting the points and creating a line between them, but i would be to long to do it if i would like to divide in many more points, and try to connect them using list item... i went looking around for a bit, i think its possible to do it with a path mapper or a flip matrix, althought i have no clue how to make it.
You will find enclosed, some screenshots...If anyone could give me any tip, i thank you all in advance.Have a nice day.+Joan…
Added by Joan tarragon at 7:38am on December 5, 2011
at your original list of numbers, if I am to go through and check manually to see what I should be getting out, I think you should only get a few outputs (which is why I was confused by all the outputs at the end of the definition.
For example, just as an example I started with X1 as 279 (item index 11). When I did the math, the only indexes that I got were 15,28, and 33.
This is because:
since 279 is positive, look for next number that is at least 180 less or 360 more than X1.
the value of 78 (item index 15) is the first value to satisfy this requirement.
Then, since 78 is smaller than 279, we are looking for the next value at least 180 more or 360 less than 78.
The value 272 (item index 28) is that next value.
Then since 272 is larger than 78, we are looking for the next value at least 180 less or 360 more than 272.
The value 52 (item index 33) is the next value.
So the definition should output the following:
indexes 15, 28, 33.
Does that make sense?…
Added by Brian Harms at 4:20pm on December 10, 2011