re-organized code, the preview at "(1)" is static, before the simulation; it is hidden to see the simulation. The preview at "(2)" is the simulation, which traces each tool path and then reveals each one piped.
…
Added by Joseph Oster at 5:56pm on November 1, 2017
ital; aproveche esta oportunidad y vea la demostración en vivo: Lugar: Escuela Digital - Mexico D.F. Hora: 7:00 - 9:00 pm Con el apoyo de: ESCUELA DIGITAL - Metzli Valle metzli@escueladigital.com.mx…
ee 3)
{5}
0 15
{6}
0 16
And I want to place points at every possible combination of these coordinates, treating Tree 1 as X coordinates, Tree 2 as Y coordinates, and Tree 3 as Z coordinates. Also, I would like the list of points to be a tree with paths corresponding to the coordinates. Wouldn't it be nice if I could plug these trees into a Point XYZ, with a new "branch cross reference" method, and get the following result?
{0:3:5}
0 {10.0, 13.0, 15.0}
{0:3:6}
0 {10.0, 13.0, 16.0}
{0:4:5}
0 {10.0, 14.0, 15.0}
{0:4:6}
0 {10.0, 14.0, 16.0}
{1:3:5}
0 {11.0, 13.0, 15.0}
{1:3:6}
0 {11.0, 13.0, 16.0}
{1:4:5}
0 {11.0, 14.0, 15.0}
{1:4:6}
0 {11.0, 14.0, 16.0}
{2:3:5}
0 {12.0, 13.0, 15.0}
{2:3:6}
0 {12.0, 13.0, 16.0}
{2:4:5}
0 {12.0, 14.0, 15.0}
{2:4:6}
0 {12.0, 14.0, 16.0}
In this form of cross referencing, every combination of individual branches from the different lists is used as separate input, and the output for each combination is put onto a branch in the result whose path is the concatenation of the input branch paths used.…
Added by Andy Edwards at 7:03pm on November 3, 2009
segments (ie. polylines)
2 = conic section (ie. arcs, circles, ellipses, parabolas, hyperbolas)
3 = standard freeform curve
5 = smoother freeform curve
The higher the degree, the less effect a single control-point has on the curve, but the further that weak effect reaches. Degree=5 curves are smoother, but it's also harder to add local details to it without adding a lot of control points. Rhino supports curves up to degree=11, but you almost never need more than 5.…
cognises the importance of providing space for the local creative economy of the Samba Schools within the Port of Rio de Janeiro, after having ignored their incorporation within the Porto Maravilha Waterfront Regeneration Project. Using this new incorporation strategy as our impetus, the Rio de Janeiro Visiting School will work directly with this initiative and aim to broaden its scope and accessibility in an attempt to foster a diverse public space for the Cidade de Samba (Samba City) infrastructure, a large warehouse complex built by the city for the top Samba Schools in the Port of Rio, which currently has no connection to the waterfront cruise-terminal tourist infrastructure, nor any type of amenities for the general public.
The projects will include the design of both permanent structures and temporary interactive installations transforming the existing closed production area of Samba City into an open space linked to proposed leisure itineraries along the waterfront. Structures will be designed with computational design methods and built with digital fabrication techniques with the assistance of local artisans combining new materials and processes with reappropriated Carnival paraphernalia. Students will build both models and partial one-to-one prototypes of their urban, architectural and interactive design proposals.
Instruction for the Visiting School workshop series will be led by AA Tutors and Assistants and local architects and specialists, the Escola de Carnaval Artistic Directors, and Carnival float-fabricators. Specifically, participants will learn computational design using rhino, grasshopper, processing, and arduino as well as the use of c.n.c. milling and routing, laser cutting and rapid-prototyping. No previous experience is necessary. The workshop is open to architecture and design students and professionals worldwide.
For more info: brazilvisitingschool@aaschool.ac.uk or +55 11 3062-3522…
ggle A
7. Toggle A
8. Toggle 2
9. Toggle 3
10. Toggle A
11. Toggle A
12. Toggle 3
I was thinking to use somehow slider and animate option....but without luck
Any idea would be appreciated…
this, you'll have no horizontal force at the roller, but you will have it at the pinned support. If you wouldn't, then the structure will be displaced.
Usually, in 2 dimensional structures, if you want to know if an articulated structure is isostatic (as opposed to hyperstatic, which is what you have right now) is to use the following formula:
b+c-2·n=0;
b being the number of bars, c the number of constraints you have and n the number of nodes. In your case: b=19, c=3 (displacements constrained in X, Z at your pinned support and only constrained in Z at your roller support) and n=11, so: 19+3-2·11=0.
I recommend you to download the app SW Truss, as it's very useful to check your results instantly.…
not sure about my method used to obtain the result.I think is really complex; do you know a smart method to simplify all my equation?
thanks guys!! :D…