erations, is not it?
This is what I finally want and how I plan to do it:
In the starting tree, points are listed accordingly to the (11) 4-side-panels they belong to. I need to do a tree where each of the 11 lists contains not the points composing the panels but the points code of the points composing the panels. the point code is the number in the flattened list that refers to the points (like, panel 1 is made of points n 0,1,4,18, and so on). To do this, I suppose that I will use my tree of 11 lists of 33 true-false values, and apply it to cull 11 times a series of numbers from 0 to 32. I ll post it if it works!…
ror "nighttime"
how could that be - must be in the weather file i assume - is there anyway to fix this ?
suncalc.net gives me the following
00:00—02:17 — night
02:17—03:43 — astronomical twilight03:43—04:39 — nautical twilight04:39—05:19 — civil twilight05:19—05:23 — sunrise05:23—21:11 — daylight21:11—21:15 — sunset21:15—21:55 — civil twilight21:55—22:51 — nautical twilight22:51—00:17 — astronomical twilight00:17—00:00 — night
plz help - thank you !!!
…
output will show a tree with 3 branches of 4 integers each that I can pass on to other components. What is the best way to do it?
I have tried creating a tree and using a for loop to do so, but it didn't work.
Thank you for your help.
…
7, 9, 12 and 13 to be able to rotate freely around the y axis at nodes 2, 3, 6, 7, 10 and 11 respectively. The last 2 conditions, for elements 12 and 13, doesn't give any problems, but the first 4 does.
Any help?
…
e
7. True
8. True <-- this one
9. True
10. False
11. True
12. False
13. True
14. True <-- this one
15. True
16. False
17. True
18. False
19. True
20. True <-- this one
21. True
22. False
23. True
24. False
25. True
26. True <-- this one
27. True
28. False
29. True
30. False
31. True
32. True <-- this one
33. True
Any idea how I can solve this?
Thanks!…
can gain that much. If you used nested "if else" statements or "andalso" statements in the previous version most of the iterations should stop after the first distance comparison.…
Added by Vicente Soler at 2:36pm on December 1, 2012
in the desired order.
0 = 0
1 = 1
2 = 6
3 = 7
4 = 8
5 = 9
6 = 12
7 = 13
8 = 2
9 = 3
10 = 4
11 = 5
12 = 10
13 = 11
Where the first number is the index and the second number is the actual sorting key. Then you sort these keys while sorting your curves in parallel using the A input of the Sort component.
--
David Rutten
david@mcneel.com
Poprad, Slovakia…