e case pictured already: don't bother how this truss is made and never mind that the def attached looks like an "add-on" (no components) - because it could be (so don't get stuck on that, it's irrelevant). In fact since the critical part (the 99% of the whole) if only doable with code ... it makes sense to do the rest with code as well (but that's my personal preference anyway, he he). Note: Balls are excluded from the demo.
You can toggle what "class" of struts is gonna being made with these booleans:
You can vary the sliders and if the code thinks that you make a valid input ... it obeys, he he.
But the big questions are:
1. Can you work with this in some interactive way? I mean vary any slider and ... wait ... for some change. Although the MERO components here are created ONCE and then placed around (minus obviously the tubes) ... they are placed as copies of the "donor" object (not instance definitions) creating a vast "pool" of "unnecessary" data.
2. What happens if you bake these little thingies? What file size you get? Is it OK?
But the bad news are that as I said ... this is ... NOT a task for a novice ... nor you can handle this get-a-truss-and-make-a-MERO-thing goal with half-measures: either you should do it properly ... or abandon ship.
NOTE: Load R file first (nothing is internalized).
Moral: even if this was made with components ... it wouldn't serve much.
best, Peter…
doing this with the current tools or a bit of scripting since the Flickr API allows you to make requests in a REST format, but utilizing the Flickr.net API library makes it much simpler.
First and foremost, you need a Flickr API key...do you have one of those?
A great way to get to know the Flickr API is with the API Explorer. Here is a link to the page for the flickr.photos.search method explorer: http://www.flickr.com/services/api/explore/flickr.photos.search
The cool thing about this page is that it generates the REST Http call towards the bottom. So, here is what I did:
1. Grab the coordinates of the bounding box per Flickr API request:
bbox (Optional)
A comma-delimited list of 4 values defining the Bounding Box of the area that will be searched. The 4 values represent the bottom-left corner of the box and the top-right corner, minimum_longitude, minimum_latitude, maximum_longitude, maximum_latitude. Longitude has a range of -180 to 180 , latitude of -90 to 90. Defaults to -180, -90, 180, 90 if not specified. Unlike standard photo queries, geo (or bounding box) queries will only return 250 results per page. Geo queries require some sort of limiting agent in order to prevent the database from crying. This is basically like the check against "parameterless searches" for queries without a geo component. A tag, for instance, is considered a limiting agent as are user defined min_date_taken and min_date_upload parameters — If no limiting factor is passed we return only photos added in the last 12 hours (though we may extend the limit in the future).
So, I went to Google Earth, picked a city (London, UK) and dropped two pins:
This gave me two locations, which I can put into the Explorer Page next to the bbox option. Here is what I put for these two points: -0.155941,51.496768,-0.116783,51.511431
2. Check has_geo
3. In extras, type in geo
4. Make the call!
You will see a list of responses in an XML format, these responses will be from the first page. Geolocated photos are limited to 250 / page, so you will have to grab them page by page.
If you want to add more options (minimum upload date, maximum upload date, etc) you can do this as well)
The best is at the bottom, you get the full http call for this: http://api.flickr.com/services/rest/?method=flickr.photos.search&api_key=ffd44f601393a46e86aa3a5f8a013360&bbox=-0.155941%2C51.496768%2C-0.116783%2C51.511431&has_geo=&extras=geo&format=rest&api_sig=b42330e5d1523bd5fe60c2ad43acde99
Notice this call has some other api key, you should eventually replace this with your own.
You could copy and paste this into a browser and you will get the results with the latitude and longitude:
So this is really what you need to know to do this through GH. Since gHowl has an XML parser component that can access files on the web, you should be able to use the same http call into this component.
Eventually, we get a response, and we need to grab the lat and lon data. With gHowl we can map these to xyz coordinates, and generate the heatmap...this is just a linear mapping:
Attached are both the Rhino file and the Grasshopper file, as well as the image underlay.
I am working on a series of components that makes this more straightforward, but for now, this should get you started.
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f my list.I don't understand why, but I guess I must be too young user ^^In the original list, i have a path {0;0;0;4} with two index and after the random node, {0;0;0;4} has 88 index.Items are not correct?I would have a comparable structure has the right list on my jpg (photomontage...)How I can do that?Thank you in advance
…
robablemente las uniones son forzadas/rotadas levemente para que calcen.
Probablemente se puede variar el angulo de 90° entre cada pieza a un angulo que permita crear el octagono perfecto, pero habría dos posibilidades de giro entre cada pieza.
Tal vez el problema hay que repensarlo desde el octagono/poliedro que forman los triangulos en el modelo y luego generar los triangulos.
Bueno aca mi definicion y algunos comentarios:
- Hoopsnake pide una condicion inicial que solo la utiliza en la primera iteracion (input S).
- Luego hay que definir el algoritmo reiterativo/recursivo que es toda la parte de abajo. Como input se utiliza el output S de hoopsnake (en la primera iteracion es la misma informacion que ingresaste en S).
El resultado de este algoritmo/proceso vuelve a ingresar a hoopsnake en el input D para una nueva iteración.
- El output H es el historial de toda la geometria/datos procesados en las iteraciones.
Ahora te explico el algoritmo:
- Se toma el triangulo y se sacan los puntos en las esquinas.
- Se revisa si los puntos estan contenidos en otro triangulo existente y hago cull para dejar los libres (ocupo el output H del hoopsnake para ver los triangulos de las iteraciones anteriores). En la primera iteracion hago un bypass para dejar todos los puntos iniciales libres (ya que no hay historial en el hoopsnake).
- La parte de abajo es para elegir una de las dos opciones max disponibles (tu comentaste arriba que habia tres opciones... en realidad son tres opciones en la inicial, luego son solo dos opciones. No se que va a pasar si se se completa el octagono, teoricamente habría solo 1 opcion disponible, pero no pude reproducirlo por el problema geometrico).
A modo de ejemplo, en la imagen le deje todas las opciones disponibles y conecte directamente (dos para el triangulo) para tratar de generar los octagonos.
- La parte final es simple, desde el centro del triangulo se genera una linea hacia las opciones disponibles para generar un plano perpendicular para la simetria y luego se rota en 90° (que creo debería ser otro angulo). Puedes mover el slider del plano perpendicular para generar la interseccion deseada en los triangulos (0.5 para interseccion completa).
Como ya te indicaron, yo tampoco hice el tema de las areas.. pero deberia ser simple en mi definición: Calculas el area del output H (triangulos), aplicas flatten, mass addition y si el numero resultante es mayor al area de la placa que quieres, debería generar un valor falso que va en el input B de hoopsnake.
Sorry que no haya ocupado tu definicion, pero ocupe un grasshopper antiguo y ademas ya había solucionado un problema similar con un alumno el semestre pasado, asi que realicé lo que me acordaba :D
Saludos y suerte!
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t, you can see 6 (+) signs with what you can add (A,B,C,P,Q,R).
Let's say you add A = 90 and B = 50.
Now you can't add the third angle (cause its 180-(50+90) = C output).
What you can add at the moment is P,Q,R.
You choose to add P = 10.
There is no more a possibility to add Q and R.
All component outputs now give us the data.
2. Triangle with P,Q,R
When you zoom the component, you can see 6 (+) signs with what you can add (A,B,C,P,Q,R).
Let's say you add P = 15, Q = 20.
Now if you add R, the component's outputs all the angles and edge lengths.
If R > P+Q then component throws warning. (> or >= ?)
You cannot add A,B or C anymone.
3.Triangle with P,Q and C
When you zoom the component, you can see 6 (+) signs with what you can add (A,B,C,P,Q,R).
Let's say you add P = 15, Q = 20.
Now if you add C (angle), the component's outputs all the angles and edge lengths.
You cannot add A,B or R anymone.
To make it all easier, disable the possibility to internalize the data.
Tolerance issue... Maybe round the angles always to floor , with 0.1 precision ?
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We are posting a few experiments, created with the work-in-progress RABBIT 0.2. We plan to release it within a week or two…
RABBIT 0.2 has a lot of new features:…
Added by Morphocode at 8:42am on February 23, 2010
being driven by the wii nunchuck... But, here's my issue. I tried it first by having the output from the listener be a 6-digit number... so, I'm using the (CInt(Val(StoredValue))) command and it's writing out 181130... and I can easily split it up selecting the Left(x,3) or Right(x,3)... I first rant that number through a Format("{0:000000}",x) so that even if one of the accx or accy numbers were a 2-digit number (so my overall number would only have 5-digits)... with this Format function... I'm always assured a 6-digit number. And this method works... except...
If the first group of numbers coming in only has 2-digits... So, lets say the accelerometer read out of the first one (accx) is 89. Let's say the accy read out is 119. So, when I run this through the Format function to make it have at least 6 digits, my number now reads 011989. So, if I were to take the first three numbers on the right, my read out would be 989... which is much higher than my expected (60-180 range that is really coming over the Serial Port)... So, I'm back to where I started... in that I need to figure out a better way to split up the data.
Which brings me to your method. I tried it as well... in fact, I added a comma in the serial readout, so the string coming out of the listener reads 89,119. So, I can use your trick to go look for a delimeter and then read to the left and right a certain number of digits... The problem I still have is that the data going into the function is a string, and thus even if I split the 3 digits to the right of the comma out (so, my output says 119)... it's still a string, and my number parameter is still red. In your picture above, was your original 181 130 a number or a string? My guess is that it was understood as a number, because your number parameters at the end are accepting the value. But, in my case... I'm still stuck with the inability to convert a string to a number... Does this make sense? And are their any other workarounds?…
Added by Andy Payne at 9:42am on September 3, 2009
st sampled into data trees (if not we must "add" them "manually" == code: get this item from Rhino and put it there) into collections.
2. Then we must perform some kind of selection(s) on a per individual item basis and THAT is in 99% of cases "manual" (== code) or on a per "global basis" (hard or soft clusters et all == code). If clusters are hierarchical and some kind of dendrogram is required ... this obviously means ... er ... more code.
3. Doing the 2 we use some kind of input by means of sliders (say pairs of 2: for branches and items) and therefor MAY their values cause slider control issues (== code). For instance IF this slider yields a x event > do this and that to some other sliders.
4. Then perform the "histogram" required and obviously treat this as just a variant (i.e. a possible solution out of a given collection witch is variable) meaning ways to "store" this into parameter(s) (as persistent data). This also requires code.
In a nutshell (and oversimplified): given a collection of "shapes" pick some make the histogram, store the result (or do something with that and store the outcome as well) recall some other for any reason, modify it, stored it ... and then repeat until the end of time (or worst: until you are out of espresso).
As I said: NOT a task for a novice AND NOT a task for someone not familiar with code matters (But I guess that you qualify in both areas, he he).
I do this type of things day in day out (but for real-life AEC purposes) therefor I could make a "simple demo" (add some "" more) but ... well ... you are warned, he he
But in case that you take the wrong decision (you are warned) we must use Skype a bit.…
ned' as this is kind of unknown to me, which is why I wanted to look for a tool or script that might generate some geometry between the two. The fundamental principle is that the input meshes must retain 90+% of their original geometry (ie not deformed into an approximated wrapped shape) but be joined together by some sort of mesh geometry which acts as a link between the two shapes. The form for this could be highly abstract and doesn't need to conform to any parameters other than allowing the original meshes to be highly visible. I hope that makes sense, it may only be clear in my mind now that I have pursued it this far!With regards to the geometry wrapper, I found the example file that you sent us and attempted to plug in similar variables with my meshes, however the values returned by the geometry wrapper are constantly zero, no matter what I seem to change. I am currently plugging the mesh into a bounding box, which forms the box for both the geometry wrapper and iso surface and then inputting integers for the remaining parameters, though I'm not quite sure what actions these are performing. Would it help if I could send you my definition? I'm currently trying to internalise my meshes, though my rhino keeps crashing when I try! If you aren't able to follow any of the above let me know and I'll try and put together some simple diagrams that may explain it better.
Thanks,
Tom…
Added by Tom Jelley at 3:28pm on November 12, 2014