une 7 at Madison Square Garden. Promoted by Miguel Cotto Promotions, Top Rank®, DiBella Entertainment and Sampson Boxing, in association with Maravilla Box, Tecate and Madison Square Garden.Fight Tickets and PPV InfoCotto vs Martinez tickets are now available for purchase online at Ticketnetwork. To charge by phone with a major credit card, call Buy Tickets Center at (855) 859-4045. The fight will be produced and distributed live by HBO Pay-Per-View®, beginning at 9:00 p.m. ET/6:00 p.m. PT.Hall of Fame trainer Freddie Roach is devising a cunning and effective strategy to, badger, outfox, and hound WBC middleweight champion Sergio “Maravilla” Martinez (51-2-2, 28KOs) into a brush with defeat, on June 7th at Madison Square Garden. Roach is training former three division world champion Miguel Cotto (38-4, 31KOs) for the match.“We have seen Martinez fights. I observed him closely when I was in Julio Cesar Chavez Jr’s corner, and he’s very fast. But…like all opponents he can be outboxed. If Miguel focuses on his body, Martinez will loose his speed and that’s when we will knock him out,” Roach mused.Cotto (38-4, 31 KO) and Martinez (51-2-2, 28 KO) will meet for Martinez’s WBC middleweight title and The Ring Magazine championship at Madison Square Garden, promoted by Top Rank, DiBella Entertainment, and Miguel Cotto Promotions.“Face Off” will premiere on Saturday, May 24 at Midnight EDT (so technically, the first minutes of Sunday, May 25, technically), after the May 24 HBO Boxing After Dark card, featuring Bryant Jennings vs Mike Perez, Daniel Geale vs Matthew Macklin, and Edwin Rodriguez vs Marcus Johnson.Other air times:HBO air times include: May 24 (12:00 a.m.), 25 (10:00 a.m.), 27 (3:15 p.m. & 2:30 a.m.), 28 (12:30 a.m.), 29 (5:30 p.m.), 30 (10:30 a.m.), 31 (7:00 p.m.) and June 3 (12:30 p.m. & 3:30 a.m.), 5 (1:15 a.m.), 6 (6:45 p.m.) and 7 (10:45 a.m.).HBO2 air times include: May 25 (5:30 p.m.), 26 (10:45 a.m. & 3:30 a.m.) 30 (4:00 p.m.) and 31 (11:30 p.m.).…
could accomplish this by adding something like '5.0 + Slider * 3.0' into the expression field... (and having an integer slider with domain 0 to 6).
--
David Rutten
david@mcneel.com
Poprad, Slovakia…
Added by David Rutten at 10:19am on February 24, 2011
hes and each branch has 21 items.
so that there'll be 30 branches.
referring back to this discussion.
http://www.grasshopper3d.com/forum/topics/dividing-a-list-into-groups
the problem is
when i put this into a path mapper
first branch has 11 items
and the last branch has 10 items.
and make 31 branches rather than 30 branches
seems to me it's behaving oddly..
how can i make this list into
30 branches
21 items each?
…
ll these 12500 points.
Group 1 would represent the point located at 0, 5, 10, 15, 20 etc.
Group 2 - 1, 6, 11, 16, 21 etc.
Group 3 - 2, 7, 12, 17, 22 etc.
Group 4 - 3, 8, 13, 18, 23 etc.
Group 5 - 4, 9, 14, 19, 24 etc.
I can create the pattern but the selection of points are all the points in row 0 and then all the points in row 5 and so on.
I would like the selection of points to start at the bottom left, and sequentially continue to the right and then continue on the 2nd row (left to right & bottom to top). i am hoping the pattern i am trying to achieve is more understood with the quick screen capture I uploaded.
the end goal is to be able to select all the points in the grid that are in each pattern.
Thanks in advance for any guidance with this. …
Added by Alyne Rankin at 6:53am on October 11, 2017
here are 168 contours with 11 frames each. If I change the direction of contours, they look fine, 168 lines. Now change the count in horizontal frames to 11 and I end up with: 20 frames. There are 168 list items, but all with 0 values inside, except the second one which has 9 values and the third one which has 11 values. Makes no sense at all!
I will attach the grasshopper file, you can have a little play yourself.…
} (N=11) {0;1} (N=11) {0;2}(N = 11) {0;3}(N = 11) {0;4}(N = 11)
2. I run the Points that are coming out from the Divide Curve Components through the Path Mapper components with this definition:
{A;B} (i) > {A} (i)
3. I run data coming out from Path Mapper component through:
a) Parameter Viewer component and the result is:
{0} N=11 (data with 1 branches)
b) Point > Panel and the result is:
collection of 11 point (N=11) which is the exactly the same as the collection of point belonging to {0;4} (N = 11).
So, here is the question:
why the collection of points coming out from the Path Mapper {A;B} (i) > {A} (i) component is the same as the collection of points belonging to the curve {0;4}(N = 11) ?
Anyway ... It 's the first time I ask a question here... so I would like to thank you for what you do with your work! Thank you! You are really great!…
First use a series component with start=1, step=42, count=3
Use the output to create a new series component with start=existingseries, step=1, count=11