Search Results - 11选5开奖结果爱彩乐-『1TBH·COM』11选5前三直最大遗漏多少期--2023年3月19日5时52分52秒.H5c2a3.t93brrchr

Comment on: Topic 'delete the duplicate data in a list.': Would it possible to remove all the items which has clones? For example: [1, 1, 2, 3, 4, 3, 5, 6, 6] to [2, 4, 5]; Added by Kirill at 5:45am on April 19, 2020

Topic: Transpose list: The best way is to use a C# or a VB component to transpose these lists. I think in C# you can use transpose directly. You can ask this on the VB/C# forum on our new website, www.grasshopper3d.com - Scott On May 27, 3:56 am, Tonsgaard wrote: > Being a long time user of Generative Components trying to use > grasshopper i miss the "transpose" command. > I have a point list like this: > > 0, 1, 2, 3, 4, 5 > 0, 1, 2, 3, 4, 5 > 0, 1, 2, 3, 4, 5 > 0, 1, 2, 3, 4, 5 > 0, 1, 2, 3, 4, 5 > > and a want to transpose dimensions to: > > 1, 1, 1, 1, 1 > 2, 2, 2, 2, 2 > 3, 3, 3, 3, 3 > 4, 4, 4, 4, 4 > 5, 5, 5, 5, 5 > > Surely I am not the first in need of this... > how would i go about and do this...? I suppose its quite easy in VB > script, but being used to GC's C# like language, I kinda dont know how > to do this... > > thanks... > > Tonsgaard…; Added by Jes Tonsgaard at 9:06am on May 28, 2009

Topic: weaving indices: n =5; {0;b} n=3; {0;d} n =5.can anyone tell me how to do it? thanks!…; Added by Clemens Klein at 5:09am on September 24, 2010

Topic: Math Addition Problem: s AB …; Added by Agneesh at 8:27pm on May 18, 2015

Comment on: Topic 'Line Art / List of Points / shift list?': m reading it now. thank you so much for your responses!…; Added by Alyne Rankin at 1:06am on November 5, 2017

Comment on: Topic 'offsetting control points on a curve': 'reverse' reverses the order of the items in a list e.g. 1, 2, 3, 4, 5 would become 5, 4, 3, 2, 1; Added by Sam Wood at 2:45am on October 21, 2011

Event: McNeel Asia - Rhino原厂培训中心暑期课程开始接受报名: 设计业制定的曲面造型技术精粹课程，涵盖基础内容到高级经验技巧。与常见的以介绍软件功能为主的培训课程不同，不仅培养学员全面的曲面造型的技能、介绍曲面造型的经验和技巧以及如何综合的运用到建筑造型中，且提供一整套基于Rhino平台的造型、表皮、钢构、施工图与模型信息化的解决方案与技能，这种“技能”的学习才是是本课程的价值所在！点击了解课程详细介绍... Grasshopper 参数化课程基于Rhino平台的参数化解决方案课程，授课注重培养学员灵活使用编程技术以解决实际问题的能力。课程深入到编程的整个过程，从编程思维方式、工具运行原理到用法细节做详尽的解释。辅助学员掌握整个过程中遇到的思路和技术等方面的问题，主要包括反向逻辑思维能力的培养、建立清晰的编程逻辑思维能力、GH 的程序设计理念与并行数据结构深入理解和控制。点击了解课程详细介绍... V-Ray for Rhino 建筑渲染表现课程全面讲解V-Ray渲染引擎高级渲染表现方法，全面剖析渲染技巧以及更进阶的运用、并且得到更加拟真的渲染影像，轻松完成设计所需的照片级的提案图片。无需繁琐的转档即可在Rhino中享受 Vray 的高效、快捷与超真实表现方法。点击了解课程详细内容... 课程报名课程即日开始报名，开课一周前停止报名，名额满提前报名结束。现在就在线提交报名表、报名参加课程... 提示：近期大陆地区有部分培训机构冒充Rhino授权原厂培训机构或原厂授权培训讲师，目前在大陆地区仅有 McNeel Asia 原厂培训中心，并没有授权其他培训中心展开原厂的相关课程，敬请留意。可以在我们网站查询相关资料。查询大陆地区原厂授权培训中心名单... 授课时间安排联系人 McNeel 深圳办事处: Jessesn (0755-29642189) McNeel 上海办事处: Dixon (021-56496412)…; Added by Jessesn at 1:09am on May 20, 2013

Blog Post: If ghx is a language ...

Added by zlyx at 1:51am on August 5, 2010

Topic: Customize Componenet In Grasshopper: x and min values for x,y,z and calculate energy for each optionand collect these results in excel sheet ... option No. x y z Annual coiling demand(by DIva) 1 10 10 10 2 10 15 20 3 11 10 19 4 12 14 17 5 15 16 15 6 16 11 14 7 18 12 12 . . etc Regards ... hossam Hossam.wefki@gmail.com…; Added by Hossam Wefki at 4:32am on May 22, 2014

Comment on: Topic 'recursion in c#': n; n = (int) (Math.Log10((double) nfaces / 20.0) / Math.Log10(4.0)); double t = (1.0 + Math.Sqrt(5.0)) / 2.0; double c = Math.Sqrt(1 + (1.0 + Math.Sqrt(5.0)) * (1.0 + Math.Sqrt(5.0)) / 4.0); //Icosaedron Rhino.Geometry.Mesh mesh = new Rhino.Geometry.Mesh(); mesh.Vertices.Add(-1 / c, t / c, 0); mesh.Vertices.Add(1 / c, t / c, 0); mesh.Vertices.Add(-1 / c, -t / c, 0); mesh.Vertices.Add(1 / c, -t / c, 0); mesh.Vertices.Add(0, -1 / c, t / c); mesh.Vertices.Add(0, 1 / c, t / c); mesh.Vertices.Add(0, -1 / c, -t / c); mesh.Vertices.Add(0, 1 / c, -t / c); mesh.Vertices.Add(t / c, 0, -1 / c); mesh.Vertices.Add(t / c, 0, 1 / c); mesh.Vertices.Add(-t / c, 0, -1 / c); mesh.Vertices.Add(-t / c, 0, 1 / c); mesh.Faces.AddFace(0, 11, 5); mesh.Faces.AddFace(0, 5, 1); mesh.Faces.AddFace(0, 1, 7); mesh.Faces.AddFace(0, 7, 10); mesh.Faces.AddFace(0, 10, 11); mesh.Faces.AddFace(1, 5, 9); mesh.Faces.AddFace(5, 11, 4); mesh.Faces.AddFace(11, 10, 2); mesh.Faces.AddFace(10, 7, 6); mesh.Faces.AddFace(7, 1, 8); // 5 faces around point 3 mesh.Faces.AddFace(3, 9, 4); mesh.Faces.AddFace(3, 4, 2); mesh.Faces.AddFace(3, 2, 6); mesh.Faces.AddFace(3, 6, 8); mesh.Faces.AddFace(3, 8, 9); // 5 adjacent faces mesh.Faces.AddFace(4, 9, 5); mesh.Faces.AddFace(2, 4, 11); mesh.Faces.AddFace(6, 2, 10); mesh.Faces.AddFace(8, 6, 7); mesh.Faces.AddFace(9, 8, 1); for (int i = 0; i < n; i++) { Rhino.Geometry.Mesh mesh_rec = new Rhino.Geometry.Mesh(); recursiveSubdivision(mesh, ref mesh_rec); mesh = mesh_rec; } mesh.Vertices.CombineIdentical(true, true); mesh.Normals.ComputeNormals(); mesh.Compact(); A = mesh; } // <Custom additional code> public void recursiveSubdivision(Mesh mesh, ref Mesh mesh_rec) { int ind = 0; for (int i = 0; i < mesh.Faces.Count; i++) { Point3f A = new Point3f(mesh.Vertices[mesh.Faces[i].A].X, mesh.Vertices[mesh.Faces[i].A].Y, mesh.Vertices[mesh.Faces[i].A].Z); Point3f B = new Point3f(mesh.Vertices[mesh.Faces[i].B].X, mesh.Vertices[mesh.Faces[i].B].Y, mesh.Vertices[mesh.Faces[i].B].Z); Point3f C = new Point3f(mesh.Vertices[mesh.Faces[i].C].X, mesh.Vertices[mesh.Faces[i].C].Y, mesh.Vertices[mesh.Faces[i].C].Z); ind = mesh_rec.Vertices.Count; mesh_rec.Vertices.Add(A);//0 mesh_rec.Vertices.Add(middle(A, B)); mesh_rec.Vertices.Add(B); mesh_rec.Vertices.Add(middle(B, C)); mesh_rec.Vertices.Add(C); mesh_rec.Vertices.Add(middle(C, A)); mesh_rec.Faces.AddFace(ind + 0, ind + 1, ind + 5); mesh_rec.Faces.AddFace(ind + 1, ind + 3, ind + 5); mesh_rec.Faces.AddFace(ind + 1, ind + 2, ind + 3); mesh_rec.Faces.AddFace(ind + 5, ind + 3, ind + 4); } } public Point3f middle(Point3f A, Point3f B) { Point3f AB = new Point3f(); float length; AB.X = (A.X + B.X) / 2; AB.Y = (A.Y + B.Y) / 2; AB.Z = (A.Z + B.Z) / 2; length = (float) Math.Sqrt(AB.X * AB.X + AB.Y * AB.Y + AB.Z * AB.Z); AB.X = AB.X / length; AB.Y = AB.Y / length; AB.Z = AB.Z / length; return AB; }…; Added by Laurent DELRIEU at 12:58pm on August 6, 2016