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Comment on: Topic 'divide in branches': %4} = {0;1;0} {0;0;5} --> {0;5\4;5%4} = {0;1;1} {0;0;6} --> {0;6\4;6%4} = {0;1;2} {0;0;7} --> {0;7\4;7%4} = {0;1;3} {0;0;8} --> {0;8\4;8%4} = {0;2;0} {0;0;9} --> {0;9\4;9%4} = {0;2;1} .... {0;0;19} --> {0;19\4;19%4} = {0;4;3}…; Added by Danny Boyes at 11:39am on June 25, 2011

Topic: accumulate: 13;2} ... 20.{13;12} 21. {21;0}22. {21;1}23. {21;2} ... 41. {21;20} 42. {34;0}43. {34;1}44. {34;2} ... 75. {34;33} 76. {55;0}77. {55;1} ... .... I want to grab the first 8 [0-7], the next 13[8-20], the next 21[21-42] etc so i have the (known fibonacci seq) list of numbers on the left here: C S 8 0 13 8 21 21 34 42 55 76 89 131 144 220 233 364 and i need the list on the right, so that i can select items using a Series (N=1 and S and C from the list above) and a List Item component. the simple question is: is there a component that can take a list and accumulate it in this way that I need? if not, is there anyone that can point me to a simple relevant VB example so i could easily adapt it? many thanks, gotjosh…; Added by gotjosh at 9:51am on August 10, 2011

Topic: Splitting a tree and reversing the order for alternate branches: hieve 1 2 3 4 5 6 7 8 Branch 1 14 13 12 11 10 9 Branch 2 15 16 17 18 19 Branch 3 27 26 25 24 23 22 21 20 Branch 4 Many thanks William…; Added by WT4 at 11:56am on August 16, 2016

Topic: Creating a Series that does not add continously: ards to the number before the start number... i.e. 9, 0, 1, 2, 3, 4, 5, 6, 7, 8 then it will need to repeat this pattern (continuing to count upwards) and the repeat number is based on a slider (for example 3 in the case illustrated below): 9, 0, 1, 2, 3, 4, 5, 6, 7, 8 19, 10, 11, 12, 13, 14, 15, 16, 17, 18, 29, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, if anyone has any ideas on how to create this series it would be great M.…; Added by Matthew Spremulli at 10:15am on August 9, 2009

Comment on: Photo 'klein': 这个变形的丹麦馆，你的这个扣洞的取舍关系，可以交流下嘛？如果有需要我可以分享下我的资源！; Added by Alan Ren at 9:44am on August 6, 2013

Event: McNeel Asia 冬季Grasshopper 参数化设计课程 -北京-上海-深圳: 大量实际案例的引导式教学，强调思考和分析方法，辅助学员摸透整个参数化设计过程中涉及的技术和思路环节，完善相关知识结构，建立正确且系统的参数化设计思维方式和深化学习能力。课程周期： 6 天集中课程，每天 8 小时价格：4000 4500（在校师生）/ 4500 5000（在职人员），价格均不含税 2018-2019冬季Rhino原厂同时开设的面授课程 Rhino建筑曲面造型高级面授课程北京 12/30-1/08 上海 1/11-1/20 深圳 1/22-1/31 Rhino 工业设计/艺术设计曲面造型高级面授课程深圳 1/13-1/26（最后3天为T-Splines多边形课程）现在开始报名... …; Added by Jessesn at 8:32pm on December 1, 2018

Event: McNeel Asia 2020 暑期 Rhino建筑曲面造型高级课程: 7小时+晚上2小时答疑。特别提醒：2020年Rhino原厂对原有课程内容进行了深度补充和修改，请点击这里查看补充内容介绍。课程标准价格：￥7800（在校师生）/￥6800（在职人员），价格均不含税课程优惠价格：￥7200（在校师生）/￥6200（在职人员），价格均不含税请点击这里阅读本课程完整内容介绍。 …; Added by Jessesn at 8:43pm on June 13, 2020