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algorithmic modeling for Rhino

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Search Results - 澳洲快乐8如何挣钱-『9TBH·COM』澳门大乐透49码--2023年3月19日6时46分34秒.H5c2a3.keyn8m8w9-gov-hk

Topic: Count same data inside of a list
ny 0,33 are inside the list??…
Added by Francisco Lara at 7:23pm on November 28, 2011
Topic: problème de classement
s suivantes {0;0}                                                        {0;0} 0=longueur (300)                                      0=longueur (400)   1=largeur (8)                                            1=largeur (6) 2=hauteur (20)                                         2=hauteur (8) {0;1}                                                        {0;1} 0=longueur (250)                                     0=longueur (250) 1=largeur (8)                                           1=largeur (8) 2=hauteur (12)                                        2=hauteur (12) {0;2}                                                        {0;2} 0=longueur (400)                                     0=longueur (300) 1=largeur (6)                                           1=largeur (8) 2=hauteur (8)                                          2=hauteur (20)  je souhaite réorganiser mes listes en fonction de la croissance de l'item 1 (soit la largeur) puis en fonction de l'item 2 (la hauteur) néanmoins pour chacune de ces listes les items sont indissociables . dans l'exemple de gauche la liste de rhino et dans l'exemple de droite la liste que je souhaite obtenir c'est d'abord la largeur qui va croissante puis ,lorsque les largeurs sont identiques ce sont les hauteurs qui vont dans l'ordre croissant .Les longueurs restent assignées à la liste.…
Added by Hugo to Grasshopper French Users Group at 8:08am on January 6, 2014
Comment on: Event 'Parametric design of Grasshopper course in summer'
几何形体变化 Geometrical form transform
Added by Jessesn at 8:30pm on June 6, 2012
Blog Post: Geco | Rhino2Eco WEBINAR @ 3+4 June - join US ...the registration is open until Saturday the 1st of June

Analysis in Ecotect directly from Rhino/Grasshopper through use of GECO

2013 June 3-4 + Q&A day 8:00-11:00 am…

Added by to] at 2:04pm on April 2, 2013
Comment on: Topic 'Dispatch according to number on list'
oning behind using the equality component to test for even numbers is flawed because of the data matching used by gh. It is testing like this: 0==0 True 2==1 False 4==2 False 6==3 False etc ............. Where as a Modulo 2 would work like this 0%2 = 0 1%2 = 1 2%2 = 0 3%2 = 1 4%2 = 0 5%2 = 1 6%2 = 0 7%2 = 1 8%2 = 0 9%2 = 1 ...... Also I notice you have some errors in your expressions producing Nulls. If you want it to be twice the value then you should have 2*D in the Expression and 10*D in the other .... I attach a working version.…
Added by Danny Boyes at 5:40pm on April 27, 2012
Comment on: Topic 'Erwin Hauer's Modul Hexagrid Morphing'
ou can simplify right before the Path Mapper so you have only one level.)…
Added by Damon at 12:25pm on July 21, 2014
Event: Geco | Rhino2Eco
, Thomas Grabner, Allison Weiler The class is taught in English, fully online in 2 sessions of 3 hours each and an additional Q&A day via email. The course is scheduled between 8:00 and 11:00 UTC. This means that it is scheduled between 10:00 and 13:00 for Central European Summer Time (CEST) and between 16:00 and 19:00 for China Standard Time (CST – Beijing time). Participants are expected to have a basic understanding of Grasshopper. Familiarity with Autodesk Ecotect is not required. You will be able to ask questions in the class through a live chat designed to give participants support on theory and exercises developed during the course.…
Added by to] at 1:01pm on March 28, 2013
Topic: Find subsequent values in a list
e 7. True 8. True  <-- this one 9. True 10. False 11. True 12. False 13. True 14. True  <-- this one 15. True 16. False 17. True 18. False 19. True 20. True  <-- this one 21. True 22. False 23. True 24. False 25. True 26. True  <-- this one 27. True 28. False 29. True 30. False 31. True 32. True  <-- this one 33. True   Any idea how I can solve this?   Thanks!…
Added by Anja at 1:25am on January 5, 2012
Topic: Re-arrange list groups
er of curves with variable number of divisions each, so i have something like this. {0;0} 1 Point 2 Point 3 Point 4 Point 5 Point 6 Point 7 Point {0;1} 1 Point 2 Point 3 Point 4 Point 5 Point 6 Point 7 Point {0;2} 1 Point 2 Point ....... and keepts going so what i want to do is to re-organize this list, making a new one with packages like all #1 items, all #2 items, and so on... i know that i can do this with LIST ITEM but i have to use 8 list item components if i want 8 divisions in each curve, so then if divisions changes, add more components or remove....    that's not a really good way to do it. is it any way to do it better? …
Added by Jose David Pabon at 11:06pm on February 28, 2013
Topic: Cull Pattern
ll these 12500 points. Group 1 would represent the point located at 0, 5, 10, 15, 20 etc. Group 2 - 1, 6, 11, 16, 21 etc. Group 3 - 2, 7, 12, 17, 22 etc. Group 4 - 3, 8, 13, 18, 23 etc. Group 5 - 4, 9, 14, 19, 24 etc. I can create the pattern but the selection of points are all the points in row 0 and then all the points in row 5 and so on. I would like the selection of points to start at the bottom left, and sequentially continue to the right and then continue on the 2nd row (left to right & bottom to top). i am hoping the pattern i am trying to achieve is more understood with the quick screen capture I uploaded. the end goal is to be able to select all the points in the grid that are in each pattern. Thanks in advance for any guidance with this.  …
Added by Alyne Rankin at 6:53am on October 11, 2017
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