x and min values for x,y,z and calculate energy for each optionand collect these results in excel sheet ...
option No. x y z Annual coiling demand(by DIva)
1 10 10 10
2 10 15 20
3 11 10 19
4 12 14 17
5 15 16 15
6 16 11 14
7 18 12 12
.
.
etc
Regards ...
hossam
Hossam.wefki@gmail.com…
EC
1. Between hours 1:00 to 24:002. Current document units is in Meters3. Conversion to Meters will be applied = 1.0004. [1 of 7] Writing simulation parameters...5. [2 of 6] No context surfaces...6. [3 of 6] Writing geometry...7. [4 of 6] Writing materials and constructions...8. [5 of 7] Writing schedules...9. [6 of 7] Writing loads and ideal air system...10. [7 of 7] Writing outputs...11. ...... idf file is successfully written to : c:\ladybug\Freeformtower_IDF\EnergyPlus\Freeformtower_IDF.idf12. 13. Analysis is running!...14. ......
Done! Read below for errors and warnings:
15. 16. Program Version,EnergyPlus-Windows-64 8.1.0.009, YMD=2015.04.04 23:39,IDD_Version 8.1.0.00917. 18. ************* IDF Context for following error/warning message:19. 20. ************* Note -- lines truncated at 300 characters, if necessary...21. 22. ************* 577 Zone,23. 24. ************* Only last 1 lines before error line shown.....25. 26. ************* 578 Freeformbuilding27. 28. ** Warning ** IP: IDF line~578 Comma being inserted after:" Freeformbuilding" in Object=ZONE29. 30. ** Severe ** Out of range value Numeric Field#5 (Type), value=0.00000, range={>=1 and <=1}, in ZONE=FREEFORMBUILDING31. 32. ************* IDF Context for following error/warning message:33. 34. ************* Note -- lines truncated at 300 characters, if necessary...35. 36. ************* 586 BuildingSurface:Detailed,7341.
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ouldn't the surface component only accept the number 8? it accepts 5 and 7. the grid is 7 points in the x direction and 5 points in the y direction. so shouldn't the u count be either 6 or 8?
it works with the u count at 5. i just don't understand why.
thank you so much for your patience with my questions.
…
Added by pwdarden to gHowl at 6:18pm on September 21, 2013
{1;1;4}{1;1;5}{1;2;0}{1;2;1}{1;2;2}{1;2;3}{1;2;4}{1;2;5}{1;3;0}{1;3;1}{1;3;2}{1;3;3}{1;3;4}{1;3;5}
etc...
and I want to format as a text it so it replaces the innermost branch with a letter so {0;0;1} would read A-0-1. I am able to replace all the symbols using replace text but am no sure if there's a way to convert a number to a letter.…
Added by Ryan Whitby at 12:40pm on February 3, 2015
e possible to change the component definition making possible to customize the number of outputs.Now Dispatch moves "true" values to A and "False" values to B
INPUT:
L (List to work on) -> 1, 2, 3, 4, 5, 6, 7, 8
D (Dispatch Pattern) -> True, False
OUTPUT:
A (List) -> 1, 3, 5, 7
B (List) -> 2, 4, 6, 8
Could it be possible/useful to modify it so it could dispatch items to several outputs, like:
INPUT:
L (List to work on) -> 1, 2, 3, 4, 5, 6, 7, 8, 9, 0
D (Dispatch Pattern) -> A, B, C
OUTPUT:
A (List) -> 1, 4, 7, 0
B (List) -> 2, 5, 8
C (List) -> 3, 6, 9
maybe I'm missing something and there's already a component with this function... I have been searching on the forum for half afternoon, but can't find anything about it!
Thank you!…
lues. What I want to do is combine them so that the structure would be something like:
{4;0}
{4;1}
{4;2}
{4;3}
{5;0}
{5;1}
{5;2}
{5;3}
I tried the method here, but it didn't give me what I wanted, it was just tacking the new values onto the end, and not maintaining their paths. Any help would be appreciated. Thanks!…
Added by Dennis Goff at 8:13am on February 10, 2016
nch, xno items in one list)2 divide the list lenght value by the numer of items per branch needed3A generate a list with the series component: the step equal to the target numer of items per branch; the no of items equals the number of target branches
3B generate a list with the series component: the first number of the series equals to the number of items needed (-1 to account for the 0 index); the step size again equal to the target number of itmes per branch as 3A4 feed 3A & 3B to a domain component thus identifying the start -3A- and end -3B- of the domains by which the list will be subdivided5 use a subset component with the domains above thus creating 19 branches with lists having 5 items eachfor lists which are subdivided into branches when the target number of branches is not a multiple of the number of items contained in the list:6 identify if the target number of branches is a multiple of the list by using the modulus component fed by the list lenght -1- and the target number of branches7 identify last index in the 3B series with the item component (reversed to take the last value fed)8 add 6+7 above which dill define the start of the domain that will pick up the remanent items not accommodated in 59 add (+1) to 7 above to define the end of the domain that will pick up the the remanent items not accommodated in 510 feed 8 & 9 to a domain component11 include 10 as part of the subset in 5I'm now trying to understand the components mentioned by Michael...
sn
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the one-but-last list [4]. After running out of the n- items avalaible it should continue with the second item of list 0 and so on for all items on all the lists.
Intput, six lists of 30 items each
[0] (n=30)
[1] (n=30)
[2] (n=30)
[3] (n=30)
[4] (n=30)
[5] (n=30)
Output, 18 lists of 10 items each
[0],i=0;[5],i=4; [4],i=7;...
[0],i=1;[5],i=5; [4],i=8;...
...
[5],i=1;[4],i=5; [3],i=0;...
I thought perhaps the weave component or the relative tree item component but didn't manage to figure out how to compose the mask. I couldn't find much on how to use these. I guess it should wrap the lists, but not the items.
Any help would be greatly appreciated.…
Added by Thorsten Lang at 2:27am on January 24, 2011