5 8, and then the following values are obtain as the last one (8) plus 3, then this last one (11) plus 5, and then this last one (16) plus 8, and then it starts again: 24+3, 27+5, 32+8...
Thanks
…
Added by Jesus Galvez at 5:17am on November 27, 2012
work. If you have been looking for an opportunity to get into a new part of the software or just want to get updated on the latest developments in a 90-minute presentation, then these webinars are for you. Starting this Thursday at 12:30 EST, the workshops will begin by covering basic Ladybug capabilities and will provide a survey of the latest community resources. Each Thursday, there will be another presentation covering progressively advanced topics. In total there will be 5 workshops, each of which you can register for by clicking below:
1 - Ladybug Climate Analysis - August 25th, 12:30 PM EST2 - Ladybug Facade + Shade Design - September 1st, 12:30 PM EST3 - Honeybee Energy, HVAC + Indoor Comfort Modeling - September 8th, 12:30 PM EST4 - Honeybee Daylight + Electric Light - September 15th, 12:30 PM EST5 - Honeybee THERM + WINDOW - September 22nd, 12:30 PM EST
Notably, workshops 2, 3, 4 and 5 will feature substantial coverage of capabilities that do not currently have tutorial videos. This includes new view analysis and tips and tricks for radiation studies in webinar 2, newly-released HVAC capabilities for webinar 3, electric lighting capabilities with webinar 4, and all of webinar 5 will be brand-new hot-off-the-press development! Hope that you can attend!…
ee 3)
{5}
0 15
{6}
0 16
And I want to place points at every possible combination of these coordinates, treating Tree 1 as X coordinates, Tree 2 as Y coordinates, and Tree 3 as Z coordinates. Also, I would like the list of points to be a tree with paths corresponding to the coordinates. Wouldn't it be nice if I could plug these trees into a Point XYZ, with a new "branch cross reference" method, and get the following result?
{0:3:5}
0 {10.0, 13.0, 15.0}
{0:3:6}
0 {10.0, 13.0, 16.0}
{0:4:5}
0 {10.0, 14.0, 15.0}
{0:4:6}
0 {10.0, 14.0, 16.0}
{1:3:5}
0 {11.0, 13.0, 15.0}
{1:3:6}
0 {11.0, 13.0, 16.0}
{1:4:5}
0 {11.0, 14.0, 15.0}
{1:4:6}
0 {11.0, 14.0, 16.0}
{2:3:5}
0 {12.0, 13.0, 15.0}
{2:3:6}
0 {12.0, 13.0, 16.0}
{2:4:5}
0 {12.0, 14.0, 15.0}
{2:4:6}
0 {12.0, 14.0, 16.0}
In this form of cross referencing, every combination of individual branches from the different lists is used as separate input, and the output for each combination is put onto a branch in the result whose path is the concatenation of the input branch paths used.…
Added by Andy Edwards at 7:03pm on November 3, 2009
r itself is compiled against .NET 3·5.
I recommend you use Rhino4, .NET 3·5 and VS 2008 as a debugging platform.
--
David Rutten
david@mcneel.com
Poprad, Slovakia…
it take just 3 weeks to finish the mockup after we assign them the drawings. pretty fast
there are 5 facade company took part in, including 3 aluminum mockup and 2 GRC company.
it take just 3 weeks to finish the mockup after we assign them the drawings. pretty fast
there are 5 facade company took part in, including 3 aluminum mockup and 2 GRC company.
Not overly analogue at all - do whichever is a more interesting option for you. The 3 pieces/ 30 piece minimums are guidelines at best - just come to class with something physical.
nts me this:
[[0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 3, 4, 5], [0, 1, 2, 3, 4, 5, 6], [0, 1, 2, 3, 4, 5, 6, 7]]
this is what I wanted but how to convert this to tree in grasshopper?
In grasshopper I just get:
8x IronPython.Runtime.List…