algorithmic modeling for Rhino

Search Results - 双色球和值尾数是8和9的数『1TBH·COM』全球通彩票代理注册2023年3月19日7时59分41秒.H5c2a3.ivhduifoj

Topic: Adding two lists by index value: List 1 + List 2 = Combined List List 1: 1 2 3 4 List 2: 5 6 7 8 Combined list would look like: 1 + 5 = 6 2 + 6 = 8 3 + 7 = 10 4 + 8 = 12 That is: 6 8 10 12 …; Added by Arpan Bakshi at 2:02pm on July 28, 2012

Topic: Finding adjacent squares in a grid: ace. What I am trying to do is then take these indexes and arrange them to fit a grid - so that all shared edges meet up. e.g. Surface 0 shares edges with surfaces 7 and 8, surface 7 shares edges with 19,4, 3, surface 3 shares and edge with 8 etc. What I need to do is graphically represent this in a grid, so that I can map out the uvs and effectively solve the problem of surface seams. Does anyone have a clue how to do this kind of 2d shuffling?…; Added by Gwyll at 10:57pm on March 17, 2010

Comment on: Topic 'Grasshopper 0.8.0050 available for download': I'm running service pack 8 on windows 7 64bit. Newest GH runs fine here.; Added by Michael Pryor at 6:36pm on August 2, 2011

Comment on: Topic 'Create a tree branch': I assume that branch 0;0 has N = 10 points, 0;1 N = 7 points. In the photo the way you describe the points it is like branch 0;0 has N = 45 points, where subbranch 0;0;1 has null points, subbrach 0;0;1 has N=1 point... subbranch 0;0;9 has N= 9 points. Most likely you need to just graft you initial data tree that has the following structure 0;0 with N = 10 0;1 with N = 7 0;2 with N = 9 0;3 with N = 5 0;4 with N = 8 without a file, or a solid description of your starting data structure all these remain assumptions. …; Added by ng5 Alex at 11:19am on October 19, 2016

Comment on: Topic 'recursion in c#': n; n = (int) (Math.Log10((double) nfaces / 20.0) / Math.Log10(4.0)); double t = (1.0 + Math.Sqrt(5.0)) / 2.0; double c = Math.Sqrt(1 + (1.0 + Math.Sqrt(5.0)) * (1.0 + Math.Sqrt(5.0)) / 4.0); //Icosaedron Rhino.Geometry.Mesh mesh = new Rhino.Geometry.Mesh(); mesh.Vertices.Add(-1 / c, t / c, 0); mesh.Vertices.Add(1 / c, t / c, 0); mesh.Vertices.Add(-1 / c, -t / c, 0); mesh.Vertices.Add(1 / c, -t / c, 0); mesh.Vertices.Add(0, -1 / c, t / c); mesh.Vertices.Add(0, 1 / c, t / c); mesh.Vertices.Add(0, -1 / c, -t / c); mesh.Vertices.Add(0, 1 / c, -t / c); mesh.Vertices.Add(t / c, 0, -1 / c); mesh.Vertices.Add(t / c, 0, 1 / c); mesh.Vertices.Add(-t / c, 0, -1 / c); mesh.Vertices.Add(-t / c, 0, 1 / c); mesh.Faces.AddFace(0, 11, 5); mesh.Faces.AddFace(0, 5, 1); mesh.Faces.AddFace(0, 1, 7); mesh.Faces.AddFace(0, 7, 10); mesh.Faces.AddFace(0, 10, 11); mesh.Faces.AddFace(1, 5, 9); mesh.Faces.AddFace(5, 11, 4); mesh.Faces.AddFace(11, 10, 2); mesh.Faces.AddFace(10, 7, 6); mesh.Faces.AddFace(7, 1, 8); // 5 faces around point 3 mesh.Faces.AddFace(3, 9, 4); mesh.Faces.AddFace(3, 4, 2); mesh.Faces.AddFace(3, 2, 6); mesh.Faces.AddFace(3, 6, 8); mesh.Faces.AddFace(3, 8, 9); // 5 adjacent faces mesh.Faces.AddFace(4, 9, 5); mesh.Faces.AddFace(2, 4, 11); mesh.Faces.AddFace(6, 2, 10); mesh.Faces.AddFace(8, 6, 7); mesh.Faces.AddFace(9, 8, 1); for (int i = 0; i < n; i++) { Rhino.Geometry.Mesh mesh_rec = new Rhino.Geometry.Mesh(); recursiveSubdivision(mesh, ref mesh_rec); mesh = mesh_rec; } mesh.Vertices.CombineIdentical(true, true); mesh.Normals.ComputeNormals(); mesh.Compact(); A = mesh; } // <Custom additional code> public void recursiveSubdivision(Mesh mesh, ref Mesh mesh_rec) { int ind = 0; for (int i = 0; i < mesh.Faces.Count; i++) { Point3f A = new Point3f(mesh.Vertices[mesh.Faces[i].A].X, mesh.Vertices[mesh.Faces[i].A].Y, mesh.Vertices[mesh.Faces[i].A].Z); Point3f B = new Point3f(mesh.Vertices[mesh.Faces[i].B].X, mesh.Vertices[mesh.Faces[i].B].Y, mesh.Vertices[mesh.Faces[i].B].Z); Point3f C = new Point3f(mesh.Vertices[mesh.Faces[i].C].X, mesh.Vertices[mesh.Faces[i].C].Y, mesh.Vertices[mesh.Faces[i].C].Z); ind = mesh_rec.Vertices.Count; mesh_rec.Vertices.Add(A);//0 mesh_rec.Vertices.Add(middle(A, B)); mesh_rec.Vertices.Add(B); mesh_rec.Vertices.Add(middle(B, C)); mesh_rec.Vertices.Add(C); mesh_rec.Vertices.Add(middle(C, A)); mesh_rec.Faces.AddFace(ind + 0, ind + 1, ind + 5); mesh_rec.Faces.AddFace(ind + 1, ind + 3, ind + 5); mesh_rec.Faces.AddFace(ind + 1, ind + 2, ind + 3); mesh_rec.Faces.AddFace(ind + 5, ind + 3, ind + 4); } } public Point3f middle(Point3f A, Point3f B) { Point3f AB = new Point3f(); float length; AB.X = (A.X + B.X) / 2; AB.Y = (A.Y + B.Y) / 2; AB.Z = (A.Z + B.Z) / 2; length = (float) Math.Sqrt(AB.X * AB.X + AB.Y * AB.Y + AB.Z * AB.Z); AB.X = AB.X / length; AB.Y = AB.Y / length; AB.Z = AB.Z / length; return AB; }…; Added by Laurent DELRIEU at 12:58pm on August 6, 2016

Topic: Untitled: ) 3. KeyError(1417,) 4. KeyError(1417,) 5. KeyError(1417,) 6. KeyError(1417,) 7. KeyError(1417,) 8. KeyError(1417,) 9. KeyError(1417,) 10. KeyError(1417,) 11....... i tried different weather file but also same result. it seems i have same problem. the file am working on is the radiation file i took from the examples . whats seems to be the problem? thank you for your time…; Added by ahmad nour to Ladybug Tools at 5:20am on January 12, 2016

Topic: Shifting paths like shifting lists: {0;1;0}N=6 {0;1;1}N=6 {0;1;2}N=5 {0;2;0}N=7 {0;2;1}N=8 {0;2;2}N=9 Can you shift and wrap any of the paths A B or C? Say if I wanted to shift and wrap B by 1 to get the following... {0;0;0}N=7 {0;0;1}N=8 {0;0;2}N=9 {0;1;0}N=3 {0;1;1}N=2 {0;1;2}N=5 {0;2;0}N=6 {0;2;1}N=6 {0;2;2}N=5…; Added by roderick read at 6:35am on May 15, 2013

Blog Post: Parametric Bottle Design: English.

Hi all!

I created .ghx for Parametric Design of Bottle. I defined profile curves giving control points with slider, definition of hight, shifting, and offset　based on referenced…; Added by Atsuo Nakajima at 12:31am on July 12, 2009

Comment on: Topic 'Random reduce !': to buuleans 8) cull by pattern…; Added by Philipp at 6:26am on September 3, 2011

Comment on: Topic 'surface from points read from spreadsheet': ouldn't the surface component only accept the number 8? it accepts 5 and 7. the grid is 7 points in the x direction and 5 points in the y direction. so shouldn't the u count be either 6 or 8? it works with the u count at 5. i just don't understand why. thank you so much for your patience with my questions. …; Added by pwdarden to gHowl at 6:18pm on September 21, 2013