Search Results - 中国福利彩票83期『8TBH·COM』双色球2016145期开机号码分析2023年3月19日5时18分16秒.H5c2a3.7tnrrhfzd.gov.hk

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arnold monthe

Event: 2019新课程 | Grasshopper参数化产品设计高级课程: 程连续6天课程，这是本课程的主体部分。该阶段课程对参数化设计方法进行系统性和细致性的介绍和学习。第一阶段的课程内容并不侧重于某个具体的设计行业，是一个设计业通用的专注于介绍参数化设计方法课程。其中包括：参数化设计的运行规则、逻辑思路的分析、相关方法和概念的补充，工具的使用技巧和工作流程等等。本阶段课程的详细介绍请参考参数化设计系统课程。第二阶段：参数化产品设计深入课程本阶段课程以工业设计行业实际应用的案例为主。侧重介绍参数化设计在产品设计行业中普遍和典型的应用方法和流程。并强调在产品设计行业中遇到的一些普遍的技术难点和解决办法。这个阶段的课程以实际范例的制作过程为主，反映产品设计行业中普遍会遇到的技术难点是什么，以及该用什么方法或流程去解决，是对第一阶段学习到的方法和理解的深入运用。请注意：本阶段课程并没有新的参数化设计知识点，事实上所有本阶段运用到的参数化方法和理解都是在第一阶段课程中学习到的。因此学员必须首先完成第一阶段的参数化设计系统课程。现在就报名参加课程... 了解课程更多详细介绍... …; Added by Jessesn at 8:39am on June 8, 2019

Comment on: Event 'Parametric design of Grasshopper course in summer': 色彩矩阵 Color array; Added by Jessesn at 8:30pm on June 6, 2012

Comment on: Photo 'from simple to complex': さい。日本のことを考えると、すぐに勤勉なビジネスマンや混雑した都市の写真が思い浮かびますが、それだけではありません。この国の人々は、彼らの歴史と業績を誇りに思っている間、心のこもった、そして歓迎しています。彼らは自然との調和、静けさ、そして悟りの概念を高く評価していますが、それでも彼らは飲んだりカラオケパーティーに行ったりすることを楽しんでいます。…; Added by Masumi Ikarashi at 4:23am on July 15, 2022

Comment on: Topic '[QUESTION] How many components and parameters has GH currently?': ay how many valid permutations exist. But allow me to guesstimate a number for 20 components (no more, no less). Here are my starting assumptions: Let's say the average input and output parameter count of any component is 2. So we have 20 components, each with 2 inputs and 2 outputs. There are roughly 35 types of parameter, so the odds of connecting two parameters at random that have the same type are roughly 3%. However there are many conversions defined and often you want a parameter of type A to seed a parameter of type B. So let's say that 10% of random connections are in fact valid. (This assumption ignores the obvious fact that certain parameters (number, point, vector) are far more common than others, so the odds of connecting identical types are actually much higher than 3%) Now even when data can be shared between two parameters, that doesn't mean that hooking them up will result in a valid operation (let's ignore for the time being that the far majority of combinations that are valid are also bullshit). So let's say that even when we manage to pick two parameters that can communicate, the odds of us ending up with a valid component combo are still only 1 in 2. We will limit ourselves to only single connections between parameters. At no point will a single parameter seed more than one recipient and at no point will any parameter have more than one source. We do allow for parameters which do not share or receive data. So let's start by creating the total number of permutations that are possible simply by positioning all 20 components from left to right. This is important because we're not allowed to make wires go from right to left. The left most component can be any one of 20. So we have 20 possible permutations for the first one. Then for each of those we have 19 options to fill the second-left-most slot. 20×19×18×17×...×3×2×1 = 20! ~2.5×1018. We can now start drawing wires from the output of component #1 to the inputs of any of the other components. We can choose to share no outputs, output #1, output #2 or both with any of the downstream components (19 of them, with two inputs each). That's 2×(19×2) + (19×2)×(19×2-1) ~ 1500 possible connections we can make for the outputs of the first component. The second component is very similar, but it only has 18 possible targets and some of the inputs will already have been used. So now we have 2×(18×2-1) + (18×2-1)×(18×2-1) ~1300. If we very roughly (not to mention very incorrectly, but I'm too tired to do the math properly) extrapolate to the other 18 components where the number of possible connections decreases in a similar fashion thoughout, we end up with a total number of 1500×1300×1140×1007×891×789×697×...×83×51×24×1 which is roughly 6.5×1050. However note that only 10% of these wires connect compatible parameters and only 50% of those will connect compatible components. So the number of valid connections we can make is roughly 3×1049. All we have to do now is multiply the total number of valid connection per permutation with the total number of possible permutations; 20! × 3×1049 which comes to 7×1067 or 72 unvigintillion as Wolfram|Alpha tells me. Impressive as these numbers sound, remember that by far the most of these permutations result in utter nonsense. Nonsense that produces a result, but not a meaningful one. EDIT: This computation is way off, see this response for an improved estimate. -- David Rutten david@mcneel.com Poprad, Slovakia…; Added by David Rutten at 12:06pm on March 15, 2013

Comment on: Group 'FabCafe Tokyo': 堀川先生本日はありがとうございました。下記の質問の回答すごくよくわかりました。近日中にブログに内容をアップし、皆さんと共有したいと思います。来週もよろしくお願いいたします。; Added by Inu to FabCafe Tokyo at 9:13am on March 4, 2015

Comment on: Topic 'GH at the Workplace...Welcome Your Input': 可能就是这样的了。如果GH依然是一个类似的工程工具，在工具的把手上连接了数学、优化、思维、、、可以直接数控，衍生更多插件。犹豫的方面在站立的角度，逻辑！中世纪？延续，时间、地域，那个猴子理论上无限地打字，可以打出完整的《哈姆雷特》拉丁版，出版之前和使用GH制定方案之间，可能会有一些光速、时间、方式——1、2、3、4，A、B、C、D。不同的树枝伦理。; Added by zlyx at 6:21am on September 3, 2012