algorithmic modeling for Rhino

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Blog Post: rhinoscript of recursive box: Option Explicit

'Script written by <huhooya>

'Script version 2010年10月20日 0:47:36

Call recursivebox

Sub recursivebox()

Dim…; Added by huhooya at 3:39am on November 1, 2010

Photo: Architecture Concept no. 24 | Art Installation 5: Added by Dana_Krystle at 3:07pm on May 19, 2018

Comment on: Topic 'Optimization Strategy': If you want to place bars in a line of 24 units in 0, 12 and 18 in an optimal way, try to evaluate the length 0, 12 and 18 of the line. :VSorry i did not understand the problem. xD; Added by Daniel González Abalde at 10:10am on March 1, 2017

V-Ray 3 for Rhino Released.…

Added by Parabolic Design at 8:21am on April 5, 2017

Comment for: David Hines: WWE Royal Rumble is annual Pay per view wrestling organised in January every year. Royal Rumble 2017 results date is Jan 29, Sunday.; Added by Ramona J. Gardner at 1:10am on January 10, 2017

Topic: Data tree multiplication: 64 (= 4*16) 1) 42 (= 3*14) 2) 24 (= 2*12) Does anybody know an easy way to get to the answer? Thanks for your help! …; Added by Bas van Wezel at 8:56am on September 18, 2014

Comment on: Topic 'Clipping lines to keep only segments within a box': onsecutive points at the same height then your 'Break at discontinuities' component eliminates the middle point completely and then the 'Interpolate Curve' component gives a much bigger bump in the wrong direction. This was enough to get curves to meet from opposite sides. I fixed this by changing the heights to 1.1 or 2.9, rather than 1.0 and 3.0, but it took a little while to work it out! Sigh. I attach a new version. But I actually preferred it as it was before. See what you think! Bob p.s. in the first list, elements 11, 12, 23 and 24 go from 1 to 3; elements 17 and 18 go from 3 to 1. In the second list, elements 6, 17, 18 and 29 go from 1 to 3; elements 12 and 23 go from 3 to 1. Given the above fix, these can be easily seen.…; Added by Bob Mackay at 10:40pm on November 24, 2015

Topic: Find subsequent values in a list: e 7. True 8. True <-- this one 9. True 10. False 11. True 12. False 13. True 14. True <-- this one 15. True 16. False 17. True 18. False 19. True 20. True <-- this one 21. True 22. False 23. True 24. False 25. True 26. True <-- this one 27. True 28. False 29. True 30. False 31. True 32. True <-- this one 33. True Any idea how I can solve this? Thanks!…; Added by Anja at 1:25am on January 5, 2012

Comment on: Topic 'divide in branches': %4} = {0;1;0} {0;0;5} --> {0;5\4;5%4} = {0;1;1} {0;0;6} --> {0;6\4;6%4} = {0;1;2} {0;0;7} --> {0;7\4;7%4} = {0;1;3} {0;0;8} --> {0;8\4;8%4} = {0;2;0} {0;0;9} --> {0;9\4;9%4} = {0;2;1} .... {0;0;19} --> {0;19\4;19%4} = {0;4;3}…; Added by Danny Boyes at 11:39am on June 25, 2011