algorithmic modeling for Rhino

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Comment on: Photo 'QQ图片20140207182646': 很想知道这个的建模过程细节，或者大致的建模逻辑。前段时间我刚好试着做这个类似的，完全不会啊！; Added by 酱油 at 7:33am on February 28, 2014

Topic: Point List: bers of point) index and I called the last point as indexMax that what I wrote I am sure that I made some mistakes- so if one of you can help me I will be more then glad If abc(sin(3 * pi() * ptList / ptLast)) < 0.5 Then harmony = 3 = z, 2 = x, 1 = y A = 0 Else A = 1 n = 0 For n < ptLast If A(n) = A(n + 1) Then Zf(n) = Z(n) + 12 * A(n) n = n + 1 End If (n + 4) < ptLast Then Zf(n) = Z(n) + 12 * A(n) Zf(n + 4) = Z(n + 4) + 12 * A(n + 4) Zf(n + 2) = Z(n + 2) + 6 Zf(n + 1) = Z(n + 1) + 6 - 3 * (A(n + 4) - A(n)) Zf(n + 3) = Z(n + 1) + 6 + 3 * (A(n + 4) - A(n)) n = n + 5 End If Else M = ptLast - n For n<ptLast Zf(n) = (ptLast - n) / M * 12 * A(ptLast - M) + Z(n) n = n + 1 End Zf(ptLast) = Z(ptLast) …; Added by ome at 5:10am on April 12, 2010

Comment on: Topic 'Scripting Sliders': it, [3] the upper limit, [4] the slider position. What do you think? Matt Radlab, Incorporated 25 Drydock Ave, Floor 6 Boston, MA 02210 W| radlabinc dot com E| matt@radlabinc P| 617.440.3588…; Added by Matt Trimble at 7:54pm on November 17, 2009

Comment on: Topic 'data list manipulation': ep is to understan the logics of what you want to do, in your case, build 4 point surfaces (u also need to know the right direction to build the surfaces). Then you can write an hipotetic list (by hand in a paper) of what you want. In your case the list was (0, 1, 3, 2) (2, 3, 5, 4) (4, 5, 7, 6), etc... if you can imagine building 2 lists, each one with the sequences (0, 2, 4, 6, etcc) and (1, 3, 5, 7, etc..) then you can manage with shift and graft to finally have four lists. A( 0 1 2 3 ...) B (1 3 5 etc..) C(3 5 7 etc..) D (2 4 6 etc..). And to achieve the 2 first lists, you need to get the odd and the pair numbers. The cull pattern does that amazingy well. With a pattern True-False you get de pair numbers, and with the False-True pattern you get de odd numbers. Hope it was clear enough…; Added by Pep Tornabell at 5:32am on November 19, 2009

Comment on: Topic 'how to conect every 2 points into line when you have a lot of points': the points do not have any logic,they are ramdon.i want to connect them like 1+2, 3+4, 5+6, etc.; Added by wenyu at 3:22am on May 16, 2014

Topic: Cull identical Curves: twice. Currently there are 12 Lines but acctually i just need 6 Lines. Is there a possibility to cull identical lines? …; Added by Robert Megel at 6:31am on December 27, 2012

Comment on: Topic 'i need help..': Hey, {0} 0 {1} 1 2 {2} 3 4 5 {3} 6 7 8 9 {4} 9 10 11 12 13 14 ???; Added by Rémy Maurcot at 3:03am on December 19, 2012

Topic: Complex Data Path Split: gt;>> {1} {2;7} >>>> {2} {2;8} >>>> {3} {2;9} >>>> {4} {3;10} >>>> {0} {3;11} >>>> {1} {3;12} >>>> {2} {3;13} >>>> {3} {3;14} >>>> {4} How to do that !? Thanks in advance :D…; Added by Digit at 12:51am on December 3, 2016