retrieve indices of true values - Grasshopper2024-03-29T15:55:34Zhttps://www.grasshopper3d.com/forum/topics/retrieve-indices-of-true-values?commentId=2985220%3AComment%3A656839&feed=yes&xn_auth=nothank you! it helps with my p…tag:www.grasshopper3d.com,2020-02-12:2985220:Comment:20434592020-02-12T08:55:28.509Zyuluhttps://www.grasshopper3d.com/profile/yulu
<p>thank you! it helps with my problem.</p>
<p>thank you! it helps with my problem.</p> Hey Maeusz!I cant get this me…tag:www.grasshopper3d.com,2017-09-28:2985220:Comment:18206492017-09-28T11:18:33.785Zjens jacob jul christensenhttps://www.grasshopper3d.com/profile/jensjacobjulchristensen890
<p>Hey Maeusz!<br/>I cant get this method to work for trees with subbranches :/ know of a work around?<br/><br/>-jens</p>
<p>Hey Maeusz!<br/>I cant get this method to work for trees with subbranches :/ know of a work around?<br/><br/>-jens</p> Dzieki wielkie:)
This actual…tag:www.grasshopper3d.com,2012-08-11:2985220:Comment:6567652012-08-11T10:11:56.299ZBoleslaw Musierowiczhttps://www.grasshopper3d.com/profile/BoleslawMusierowicz
<p>Dzieki wielkie:)</p>
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<p>This actually works very nice! Thanks Mateusz!</p>
<p>Dzieki wielkie:)</p>
<p></p>
<p>This actually works very nice! Thanks Mateusz!</p> cześć :D
najprostsze rozwiaz…tag:www.grasshopper3d.com,2012-08-11:2985220:Comment:6569372012-08-11T04:41:26.177ZMateusz Zwierzyckihttps://www.grasshopper3d.com/profile/MateuszZwierzycki
<p>cześć :D</p>
<p></p>
<p>najprostsze rozwiazanie to:</p>
<p>komponent list length (podłaczamy do tego drzewa)-> nastepnie komponent series (długości z drzewa jako wejście C)-> equality (gdzie jako A dajemy drzewo a jako B pojedyncza wartosc true lub false) -> ostatni komponent to cull pattern (lista L to bedzie drzewo z wyjścia series, P to jest pattern z wyjścia equality).</p>
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<p>napisze jeszcze po angielsku, bo to dość przydatne rozwiazanie :</p>
<p>solution in english…</p>
<p>cześć :D</p>
<p></p>
<p>najprostsze rozwiazanie to:</p>
<p>komponent list length (podłaczamy do tego drzewa)-> nastepnie komponent series (długości z drzewa jako wejście C)-> equality (gdzie jako A dajemy drzewo a jako B pojedyncza wartosc true lub false) -> ostatni komponent to cull pattern (lista L to bedzie drzewo z wyjścia series, P to jest pattern z wyjścia equality).</p>
<p></p>
<p>napisze jeszcze po angielsku, bo to dość przydatne rozwiazanie :</p>
<p>solution in english :</p>
<p></p>
<p>workflow which will generate such a parallel data tree of indices consists of 4 components. first of all, take a "list length" component and connect it to your datatree. then use series (connect list length to C input) to generate all indices. next step is to cull indices which are not true (or false). you should use "equality" component and provide as A your primary datatree, as B one value (true or false). last step is to cull indices with pattern obtained with equality, use "cull pattern" to achieve that (data tree from series as list, pattern taken from equality).</p> post the filetag:www.grasshopper3d.com,2012-08-11:2985220:Comment:6568392012-08-11T03:46:16.627ZMichael Pryorhttps://www.grasshopper3d.com/profile/MikePryor
<p>post the file</p>
<p>post the file</p>