Grasshopper

algorithmic modeling for Rhino

Hi Daniel ! (and anyone who can answer my question :)

I am currently working on a wooden gridshell definition, and since I needed to keep the output geometry tree structure, I decided to stay with the old version of kangaroo.

My question is, can I give the old Bend component the input value EI for strength as it is possible with the new version? If not, what is the best way to give a realistic value to this component ? 

 I know you have already discussed this issue in older post but I still dont see how I can translate the vector you are showing in the image to a comprehensive value..

Thank's a lot in advance !

Andréanne  

  

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Please someone..I really need help on this very quickly!! 

Hi Andreanne,

You can preserve the tree structure in Kangaroo 2 using the following trick:

For calibrated values it is much easier with v2 rather than the old Kangaroo.

Hi Daniel ,

Thanks a lot for your answer !!

Could you tell me what goal object you used that uses a mesh for input so that you can output a mesh at the end?

In my last definition (see attached) I used points from a rectangular grid as input geometry so that I could create seperated (x-y axes) splines wish represented my wood laths.. I wish I could also end up with x-y organised points as output with v2, do you think it is possible?

Thanks again !  

Andréanne 

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Looking at your definition you're using a value of E=900'000'000 Pa?

What does that represent?

Hi Martin, it's epicea wood of 9000 MPa. Since I use meters in rhino I figured I had to use Pa, am I correct ?

I've switched to K2 since that post and updated de E value with a more accurate one of 12410 MPa, you can see my new definition attached, dont hesitate to commant if some things seem strange! 

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