write CSV file in python

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Permalink Reply by Mostapha Sadeghipour on February 14, 2013 at 1:31pm

Salam... Something like this should do it:

Attachments:

• hamiaCSV.gh, 2 KB

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Permalink Reply by hamia Aghaiemeybodi on February 15, 2013 at 1:20am

Mersi mard,

It's working. thanks a lot.

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Permalink Reply by Felix R. on February 14, 2013 at 5:19pm

There is also a build-in library in Python for that:

http://docs.python.org/2/library/csv.html

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Permalink Reply by Toussaint Jimenez Rojas on February 14, 2013 at 5:56pm

the CVS build-in Library doesnt work for IronPython wich is the version of python that run under Rhino 5 

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Permalink Reply by Kendra byrne on March 5, 2013 at 5:03pm

True. Has anyone found a workaround in python for this? I'm trying to read a file line by line, essentially look up a line in a file by its line number.

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Permalink Reply by Mostapha Sadeghipour on March 5, 2013 at 5:08pm

is it a csv file? I haven't tested the code but something like this should work for you:

filename = open(yourFileAddress, 'r')

for lineNumber, line in enumerate(filename): 

          print lineNumeber #print the line number

          print line.split(',')  #print the line

filename.close()

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