Remove the zeros from the list

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Permalink Reply by Alberto Moral on April 22, 2012 at 2:09pm

Hi Fernando,

Please, upload the rhino file compatible with 4.0

Hola Fernando,

por favor, sube el archivo de rhino compatible con la versión 4.0

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Permalink Reply by fernando molas garcia on April 22, 2012 at 2:28pm

Thanks Albert but it is a Python code that only runs on Rhino 5!

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Permalink Reply by Giulio Piacentino on April 23, 2012 at 2:43am

Hi Fernando,

there are other ways to approach this altogether, but I think the attached file answers your question.
It is based on this code:

Lineas = [Lineas[i] for i,e in enumerate(D) if e!=0]

I hope this helps,

- Giulio
________________
giulio@mcneel.com

Attachments:

• lineas2.gh, 2 KB

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Permalink Reply by Steve Baer on April 23, 2012 at 11:26am

I think you can even remove the enumerate call and just get it down to

Lineas = [e for e in D if e!=0]

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Permalink Reply by fernando molas garcia on April 23, 2012 at 11:54am

Thanks Steve! if I get the call to enumerate get an undesired result

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Permalink Reply by Giulio Piacentino on April 23, 2012 at 12:07pm

Mh... this is interesting and makes me now wonder: what is the goal of this exercise?
What should each variable contain?

- Giulio
_________________
giulio@mcneel.com

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Permalink Reply by fernando molas garcia on April 23, 2012 at 2:06pm

Giulio

The idea is to connect the dots with straight without repeating!

My interests as an exercise as I am new to Python. but I was surprised that I can not solveusing only GH!

With the intension of improving our understanding of Python in the environment of GH, I think it would be a good idea to propose "replace" or rewrite a definition in GH withpython code

Attachments:

• lineas3.gh, 4 KB

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Permalink Reply by fernando molas garcia on April 23, 2012 at 1:03pm

And delete the values that repinten "D" is also repeated lines!

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Permalink Reply by Giulio Piacentino on April 23, 2012 at 3:01pm

Usually what you are trying to obtain is approached in the following way, because of memory and to iterate through the whole list fewer times.

If you one day need to have the same lines twice (in the two directions), you could just construct the same line but with reversed inputs, or modify the loop for j so that it starts at the beginning of the list.import rhinoscriptsyntax as rs

L = [] # construct a new, empty list for L (lines)
D = []

for i in range(len(M) - 1):
    for j in range(i + 1, len(M)):
        if rs.PointCoordinates(M[i]) == rs.PointCoordinates(M[j]):
            continue
        
        line = rs.AddLine(M[i], M[j])    #if so, add the line
        D.append(rs.CurveLength(line))   #also, compute the length
        L.append(line)


I hope this helps,

- Giulio
____________
giulio@mcneel.com

Attachments:

• lines-fernando.gh, 4 KB

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Permalink Reply by fernando molas garcia on April 24, 2012 at 11:12am

Giulio Excellent I have a question. In quesaos is advisable to place "else" after the "if"

It would be good to create a group of style ( http://www.grasshopper3d.com/group/coffee-and-grasshopper ) amplar to knowledge of Python!

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Permalink Reply by fernando molas garcia on April 24, 2012 at 11:21am

Studying your code I saw the condition that is within the "if" not met not by how they areraised loops, so you can remove this line correct?
 Thanks for your tiermpo!

import rhinoscriptsyntax as rs

Lineas = [] # construct a new, empty list for L (lines)
D = []
for i in range(len(M) - 1):
for j in range(i + 1, len(M)):
#if rs.PointCoordinates(M[i]) == rs.PointCoordinates(M[j]):
# continue

line = rs.AddLine(M[i], M[j]) #if so, add the line
D.append(rs.CurveLength(line)) #also, compute the length
Lineas.append(line)

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