How to apply a data tree structure to a flat structure

Replies to This Discussion

Permalink Reply by David Rutten on January 12, 2010 at 4:16pm

Going one way is easy, just flatten the 204 lists. Either use a Flatten component or toggle the Flatten option on any parameter that receives the data. Going the other way (i.e. converting your list of 2244 items into 204 lists of 11 items each) is more complicated but also possible.

--
David Rutten
david@mcneel.com
Poprad, Slovakia

• ▶ Reply

Permalink Reply by Thomas on September 15, 2011 at 1:21am

Hi,

 

I've been dealing with a similar problem, but haven't found a solution from the forums. Sorry for no images, the definition is currently at a different location.

 

How about if the lists aren't the same length, but the total length of items is the same. Consider the following flat lists (short for convinience):

L1: A B C D E F G H and L2: 0 0 0 1 2 2 2 3. L1 could be a list of strings or numbers, L2 defines a category. The end result should be {0;0} A {0;1} B {0;2} C {1;0} D {2;0} E {2;1} F {2;2} G {3;0} H

Using L2 getting the target paths, or even the index where the first list should be splitted, is fairly simple.

However, I just can't find a component that can divide L1 accordingly. In order it to be useful for longer lists and larger set of categories, the solution should not rely on an array of components for each branch.

• ▶ Reply

Permalink Reply by Systemiq on September 15, 2011 at 2:00am

I am not totally sure I understand your question, but perhaps this answers it :

• ▶ Reply

Permalink Reply by Thomas on September 19, 2011 at 6:19am

Thank you!

 

That's exactly what I was looking for. Though, I had to update GH from an ancient version. Seems like the Replace component worked differently before.

• ▶ Reply

Permalink Reply by Jes Tonsgaard on January 13, 2010 at 12:56am

how about something like using a graft/weave combination on the 1D list. you shoul be able to extract a mask pattern from your multidimensional list... (list lenght as input into a list component)

• ▶ Reply

Permalink Reply by Stigvg on January 13, 2010 at 3:24am

Hi Jes and David, I need to go the troublesome road, but what your are suggesting Jes make sense, thanks for that, I will try that out.

I did hope that there was a more simple way to do it,,

• ▶ Reply

Permalink Reply by Carlos on January 13, 2010 at 7:42am

Hi,
Normally it’s a problem.
But if you have the same amount of elements on each path,
what I normally do is a series of a series, like the example.

Regards,
Carlos

Attachments:

• printscreen_grasshopper.jpg, 198 KB

• ▶ Reply

Permalink Reply by Stigvg on January 13, 2010 at 7:49am

Hi Carlos,
I just went through your example, seams to work very well, I will try it out tonight.
Tanks a lot!

• ▶ Reply

Permalink Reply by Stigvg on January 13, 2010 at 2:02pm

It works !! , very simple and nice,,, great

• ▶ Reply

Permalink Reply by Alessio Erioli on January 13, 2010 at 4:12pm

Hi all, before 06.0055 I used to apply Carlos' method, but I wanted to give a try to the path mapper component, which seems to be perfect for these issues. I eventually succeeded although I did not understand why I had to apply a strange "-5" to the destination formula (see attached image)... anybody has a clue?

Alessio

Attachments:

• Structure_apply.jpg, 155 KB

• ▶ Reply

Permalink Reply by Danny Boyes on January 13, 2010 at 5:06pm

This must be a bug because its true for dividing by all odd numbers:
(i-1)/3
(i-2)/5
(i-3)/7
(i-4)/9
(i-5)/11
....
(i-n)/2n+1

And you can't make it work for even numbers

• ▶ Reply

Permalink Reply by Carlos on January 14, 2010 at 5:19am

Hey, pretty cool Path Mapper!! I didn’t noticed.
Thanks!

Stigvg, you welcome.

• ▶ Reply