Grasshopper

algorithmic modeling for Rhino

Creating grid based on fixed dimension

Hello!

Yesterday I was searching for a solution and couldn't find any so I'm turning to you guys:

Basically I want to create a planar grid on a polyline/polysurface which is based on fixed dimension (for example 5m) between every point on the grid instead of having a fixed count of fields.

I tried to solve this problem with dividing the planar surface dimensions (for example 52m x 31m) into 5m parts and substracting the remaining lenght which can't be divided by 5 (2m and 1m so it's 50m x 30m). With this I created a rectangle over my polyline/polysurface to substract from so I have a regular divideable by 5m grid.

Maybe my process is too complicated and there's a more simple solution to my problem, so that's why I came here! :)

Regards,

David

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Replies to This Discussion

Permalink Reply by Michael Pryor on November 11, 2014 at 5:59am
An image would help
Permalink Reply by Belzebub on November 11, 2014 at 12:09pm

OK - sorry forget to add what I'm trying to achieve:

Here's basically what I want, just random curve made into surface gets divided into equal squares, but instead of 10 by 10 squares for example I want to divide it in 10m by 10m squares for a support grid - how can I achieve this?

Thanks for your reply!

Regards,

David

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Permalink Reply by Belzebub on November 20, 2014 at 2:53am

Anyone? :?

Regards,
David

Permalink Reply by nikos tzar on November 20, 2014 at 5:58am

Hi Belzebub, 

for a planar grid this should work.

Permalink Reply by Belzebub on November 20, 2014 at 10:17am

Thanks, but it doesn't really substract the polysurfaces from the grid, does it only work with polygons?

Thanks for your time!

Regards,
David

Permalink Reply by Valentin on November 20, 2014 at 11:05am

Very funny. Why because Rint component will work with planar curve inputs. You should convert your output to surface after.

Permalink Reply by Valentin on November 20, 2014 at 11:19am

And def.

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