generative modeling for Rhino
Hi everybody,
I'm fighting with a seifert surface :) ... sth like this http://drgoulu.com/2009/02/03/beaux-noeuds/
Have you got any idea?

You can use seifertview.exe to view or generate it, but how in gh?
Thanks a lot
Gianni
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Permalink Reply by Igor on June 29, 2012 at 10:28am It's not look like borromean rings.
To create this surface try Mobius component from LunchBox (set T parameter to 1.5).
Permalink Reply by cornucopio on June 29, 2012 at 12:15pm
Permalink Reply by Michael Pryor on June 29, 2012 at 12:32pm being grasshopper can do functions, and has function components, just do some research to find its parametric formula and apply it to grasshoppers components. http://mathworld.wolfram.com/SeifertSurface.html
Permalink Reply by cornucopio on June 29, 2012 at 4:47pm Hi Michael, thanks for your suggestion. On google there nothing I can understand but I've asked for help to my friend, he's math teacher, I'll update the post soon
Permalink Reply by Mateusz Zwierzycki on June 29, 2012 at 7:02pm And thats a best solution I think. Please share theory after talking with your friend.
Permalink Reply by cornucopio on June 30, 2012 at 5:25am ...maybe sth with kangaroo?
Permalink Reply by Michael Pryor on June 30, 2012 at 10:34am
Permalink Reply by cornucopio on July 2, 2012 at 10:52am my friend said me he did't do the exam of topology, so I'm alone, I've written in a math forum asking help ... I'll wait
Permalink Reply by cornucopio on July 5, 2012 at 7:38am After days and days of searching and questions and forum reading ... nothing ... the most interesting thing I found is this
http://www.singsurf.org/singsurf/SingSurf.html
maybe someone needs it
white flag for me :(
The algorithm described in section 2.3 of this paper:
http://www.win.tue.nl/~vanwijk/knot.pdf
Looks like it would be possible to implement in grasshopper without too much trouble.
That would give you the correct topology, and you could then use Kangaroo to relax it and get a smooth surface.
Permalink Reply by cornucopio on July 6, 2012 at 11:15am Thanks Daniel,
this is the definition of the topology but now how can I obtain the surface? I tried to loft but it's the wrong way. Any suggestion?
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